Answer:
there should some picture to identify right?
pls edit your question and insert the picture..
Neither of those questions makes sense, and I believe that you should not waste your time worrying about them.
#61 gives you a lot of information about a ball, and then asks a question about a glove.
#62 gives a mysterious equation, doesn't tell you what either of the variables represents, and then asks for a quantity without ever telling us how that quantity is related to the equation.
Personally, my response to both questions would be "Insufficient information given".
Answer:
pressure is equal to the net amount of force acting per unit area. Dimensional Formulae of force is M1L1T-2 and of area is L2. Therefore Pressure's dimension can be obtained by calculating Force by Area. Dimensional formula of pressure difference is M1L-1T-2.
Answer:
a) x = 4.33 m
, b) w = 2 rad / s
, f = 0.318 Hz
, c) a = - 17.31 cm / s²,
d) T = 3.15 s, e) A = 5.0 cm
Explanation:
In this exercise on simple harmonic motion we are given the expression for motion
x = 5 cos (2t + π / 6)
they ask us for t = 0
a) the position of the particle
x = 5 cos (π / 6)
x = 4.33 m
remember angles are in radians
b) The general form of the equation is
x = A cos (w t + Ф)
when comparing the two equations
w = 2 rad / s
angular velocity and frequency are related
w = 2π f
f = w / 2π
f = 2 / 2pi
f = 0.318 Hz
c) the acceleration is defined by
a == d²x / dt²
a = - A w² cos (wt + Ф)
for t = 0
, we substitute
a = - 5,0 2² cos (π / 6)
a = - 17.31 cm / s²
d) El period is
T = 1/f
T= 1/0.318
T = 3.15 s
e) the amplitude
A = 5.0 cm
That would be a conduction.
