Answer:
7.5 g of AlCl3
Explanation:
The given equation is;
NaOH + AlCl3 --> Al(OH)3 + NaCI.
By inspection, it is not balanced because OH and Clare not equal on both sides of the equation.
Thus, let's make them equal by balancing the equation.
Cl has 3 on the left, so we will make it to have 3 on the right. Same thing with OH on the right and we will make it to have 3 on the left. Thus:
3NaOH + AlCl3 --> Al(OH)3 + 3NaCI
We can see that;
NaOH has 3 moles
While AlCl3 has 1 mole
Thus, to find how many grams of AlCl3 will be required to completely react with 2.25g of NaOH ;
2.25g of NaOH × (3 moles NaOH/39.997 g/mol of NaOH) × (1 mole of AlCl3/3 moles of NaOH) × (133.34 g/mol of AlCl3/1 mol AlCl3) = 7.5 g of AlCl3
Answer:
A pathway by which counter ions can flow between the half-cells without the solutions in the half-cell totally mixing.
Explanation:
Salt bridge is a link between oxidation half and reduction half of a galvanic cell.
Functions of salt bridge are:
Maintaining electrical neutrality
Preventing cell from reaching equilibrium
For creating salt bridge, a U shaped glass tube is filled with an inert electrolyte. Electrolytes used in the salt bridge generally do not reacts with the cell chemicals.
Cations and anions of the electrolytes have same ionic conductivity and hence, migrate with the same speed.
Most commonly potassium chloride, sodium chloride and potassium nitrate are used as an electrolyte in salt bridge.
Electrolyte are generally mixed with agar agar to prevent mixing of chemicals in the two half cells.
Answer:
i donr reagly knove
Explanation: yeah i dont know
Explanation:
the correct answer will be option d 64g .
hope this helps you.
