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Alekssandra [29.7K]
2 years ago
6

To calculate the freezing point depression ___ solution's freezing point and the freezing point of it's pure solvent.

Chemistry
1 answer:
murzikaleks [220]2 years ago
8 0
I'm sure that to calculate the freezing point depression <span>subtract</span> solution's freezing point and the freezing point of it's pure solvent. According to the formula.
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Each of the organic compounds mentioned has a general formula so that we can identify the classification of a certain substance. The compound CH₃CH₂OH is an alcohol because it follows the general formula R-OH, where R is a hydrocarbon chain. In this case, the hydrocarbon chain is ethane. When a hydroxyl functional group is attached, it becomes an alcohol whose name is ethanol.
5 0
3 years ago
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Calculate the decrease in temperarure when 2.00 L at 20.0 degrees celsius is compressed to 1.00 L.
Serga [27]
I suspect that the pressure of this change is constant therefore

The equation is used from the combined gas law. (When pressure is constant both P's will cancel out P/P = 1)
V/T = V/T
Initial   Change

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2/20 = 1/T
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T = 1/0.1
T = 10 degress celsius.

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3 0
3 years ago
Which physical property can be used to classify oxygen, helium, propane, and hydrogen as being similar?
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Answer:

state of matter

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4 0
3 years ago
A gas balloon has a volume of 106.0 liters when the temperature is 25.0 °C and the pressure is 740.0 mm Hg. What will its volume
ipn [44]

Answer : The final volume of gas will be, 103.3 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 740.0 mmHg  = 98.4 kPa

Conversion used : (1 mmHg = 0.133 kPa)

P_2 = final pressure of gas = 99.3 kPa

V_1 = initial volume of gas = 106.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 25.0^oC=273+25.0=298K

T_2 = final temperature of gas = 20.0^oC=273+20.0=293K

Now put all the given values in the above equation, we get:

\frac{98.4kPa\times 106.0L}{298K}=\frac{99.3kPa\times V_2}{293K}

V_2=103.3L

Therefore, the final volume of gas will be, 103.3 L

8 0
3 years ago
What is the percent nitrogen in NaNO3?<br> 56.47%<br> 27.04%<br> 16.48%<br> 14.01%
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I think it’s :answer choice c
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