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vovikov84 [41]
2 years ago
6

When using a physical balance on what pan we place the object and why​

Physics
1 answer:
kondaur [170]2 years ago
4 0

Answer:

wood

Explanation:

  • Wooden pans are usually used
  • Wood has less density than water so it will not sink in liquid substances derived from water.
  • So during physical balance it won't affect the balance which we need
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What is the ratio of the sun’s gravitational pull on Mercury to the sun’s gravitational pull on the earth?
Marta_Voda [28]

Answer:

The answer is \frac{F_{Sun-Mercury} }{F_{Sun-Earth} } =0,3709. Let's learn why.

Explanation:

Newton's law of universal gravitation says;

F_{g} =G.\frac{m_{1}.m_{2}}{r^{2}}

Here G is a universal gravitational <u>constant</u> and is measured experimentally.

Sun's gravitational pull on mercury is:

F_{Sun-Mercury} =G.\frac{m_{sun}.3,30.10^{23}}{(5,79.10^{10})^{2} }

Therefore F_{Sun-Mercury} = Gm_{sun} 98,4366

Sun's gravitational pull on Earth is:

F_{Sun-Earth} =G.\frac{m_{sun} 5,97.10^{24} }{(1,50.10^{11}) ^{2}}

Therefore F_{Sun-Earth} =Gm_{sun} 265,33

As a result;

\frac{F_{Sun-Mercury}}{F_{Sun-Earth} }=\frac{Gm_{sun}98,4366}{Gm_{sun}265,33 } =0,3709

4 0
3 years ago
Please tell me the order the answers go. Best and most correct answer gets Brainliest.
iogann1982 [59]

See the attached picture:

8 0
3 years ago
A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with incompressib
Natasha_Volkova [10]

Answer:

F = 1958.4 N

Explanation:

By volume conservation of the fluid on both sides we can say that volume of fluid displaced on the side of the car must be equal to the volume of fluid on the other side

so we have

L_1A_1 = L_2A_2

1.20(\pi 18^2) = L_2(\pi 5^2)

L_2 = 15.55 m

so the car will lift upwards by distance 1.2 m and the other side will go down by distance 15.55 m

So here the net pressure on the smaller area is given as

P = P_{atm} + \frac{12,000}{\pi (0.18)^2} + \rho g (1.2 + 15.55)

excess pressure exerted on the smaller area is given as

P_{ex} = \frac{12000}{\pi (0.18)^2} + 800(9.81)(16.75)

P_{ex} = 2.49\times 10^5 Pascal

now the force required on the other side is given as

F = P_ex (area)

F = (2.49 \times 10^5)(\pi (0.05)^2)

F = 1958.4 N

3 0
3 years ago
What are the three most important gases in the troposphere
taurus [48]
Nitrogen, oxygen, and argon
7 0
3 years ago
An ice skater starts with a velocity of 2.25 m/s in a 50.0 degree direction. After 8.33s, she is moving 4.65 m/s in a 120 degree
Mnenie [13.5K]

The y-component of the acceleration is 0.22 m/s^2

Explanation:

The y-component of the acceleration is given by

a_y = \frac{v_y-u_y}{t}

where

v_y is the y-component of the final velocity

u_y is the y-component of the initial velocity

t is the time elapsed

For the ice skater in this problem, we have:

u = 2.25 m/s is the initial velocity, in a direction \theta=50.0^{\circ}

v = 4.65 m/s is the final velocity, in a direction 120^{\circ}

t = 8.33 s is the time elapsed

The y-components of the initial and final velocity are:

u_y = u sin \theta = (2.25)(sin 50^{\circ})=1.72 m/s\\v_y = v sin \theta = (4.65)(sin 50^{\circ})=3.56 m/s

So the y-component of the acceleration is

a_y = \frac{3.56-1.72}{8.33}=0.22 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
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