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3 years ago

What is a materials ability to dissolve in a solvent

Chemistry

2 answers:

ExtremeBDS [4]3 years ago

5 0

I believe it might be A, hope this helps!

snow_tiger [21]3 years ago

4 0

Saturation hope it helps plz give thanks to me .

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riadik2000 [5.3K]

I believe it is C) to produce

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3 years ago

Katie throws a 3 kilogram ball fast at a speed of 15 meters what is the momentum of the ball katie threw

stiks02 [169]

Answer:

Hey!

Your answer is 45kg.m/s

Explanation:

Using the formula P=M x V

(p=momentum...M=mass...V=velocity)

We do M x V

15 x 3

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HOPE THIS HELPS!!

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4 years ago

Which of the following is not an effect of acid rain? a. Corrosion of buildings c. Limestone corrosion b. Reduced cold tolerance

Novay_Z [31]

d. Reduced visibility

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4 years ago

Using the video controls, compare the wave shapes of a mosquito's buzz with the wave shape of the air boat's roar. How are the s

Illusion [34]

Answer:

The height of the waves vary. The wave height is much larger for the air boat than for the mosquito.

Explanation:

Plato question

7 0

3 years ago

Read 2 more answers

20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator

Vinvika [58]

20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator would be most suitable for this titration? The pKa of CH3CH2NH3+ is 10.75.

Answer:

Bromocresol green, color change from pH = 4.0 to 5.6

Explanation:

The equation for the reaction is as follows:

$C_2H_5NH_{2(aq)$ + $H^+_{(aq)$ ⇄ $C_2H_5NH_{3(aq)}^+$

Given that concentration of $C_2H_5NH_{2(aq)$ = 10%

i.e 10 g of $C_2H_5NH_{2(aq)$ in 100 ml solution

molar mass = 45.08 g/mol

number of moles = $\frac{10}{45.08}$

= 0.222 mol

Molarity of $C_2H_5NH_{2(aq)$ = 0.222 × $\frac{1000}{100}mL$

= 2.22 M

However, number of moles of $C_2H_5NH_{2(aq)$ in 20 mL can be determined as:

number of moles of $C_2H_5NH_{2(aq)$ = 20 mL × 2.22 M

= $44*10^{-3} mole$

Concentration of $C_2H_5NH_{2(aq)$ = $\frac{44*10^{-3}*1000}{20}$

= 2.22 M

Similarly, The pKa Value of $C_2H_5NH_{2(aq)$ is given as 10.75

pKb value will be: 14 - pKa

= 14 - 10.75

= 3.25

Finally, the pH value at equivalence point is:

pH= $\frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]$

pH = $\frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]$

pH = 5.21

∴

The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6.

6 0

4 years ago