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3 years ago

Hybridization of NH3

Chemistry

1 answer:

nadya68 [22]3 years ago

6 0

Answer:

Sp3 hybridization

Explanation:

The NH3 molecule, which consists of one lone pairs and three bond pair of electron on its valance shell due to lone pair bond pair repulsion makes bond angle of 107.5°resulting distorted tetrahedral geometry.

Hybridization =no. of bond pair +lone pair=3+1=4=sp3 hybridization

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What is the correct measurement for solubility?

Montano1993 [528]

Other commonly used units include g/L (grams of solute per liter of solution) and m/L (moles of solute per liter of solution). Solubility units always express the maximum amount of solute that will dissolve in either a given amount of solvent, or a given amount of solution, at a specific temperature.

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3 years ago

(40 Points) Complete, balance, compute the amounts of the products assuming 100% yield. 10g Na + 10g Oxygen.

Lilit [14]

13.5g

Explanation:

Given parameters:

Mass of Na = 10g

Mass of O₂ = 10g

Unknown:

Mass of products formed = ?

Balanced equation = ?

Solution:

The balanced chemical equation is shown below:

4Na + O₂ ⇒ 2Na₂O

In any reaction, the specie in short supply determines the extent of the reaction.

This reaction is not an exclusion. We need to first determine the specie in short supply and use it to estimate the amount of product since we have a 100% yield which signifies that all was used up.

let us convert to moles;

Number of moles of Na = $\frac{mass }{molar mass} = \frac{10}{23}$ = 0.435mole

Number of moles of O₂ = $\frac{mass}{molar mass} = \frac{10}{32}$ = 0.313mole

From the given equation;

4 moles of Na requires 1 mole of O₂;

0.435 moles of Na will require $\frac{0.435}{4}$ = 0.11 moles

But the given amount O₂ is 0.313, this is an excess of 0.313 - 0.11 = 0.203moles

We see that Na is the limiting reagent;

4 moles of Na gives 2 mole of Na₂O

0.435 moles of Na will give $\frac{0.435 x 2 }{4}$ = 0.22 moles

Mass of Na₂O = number of moles x molar mass = 62 x 0.22 = 13.5g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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3 years ago

The atomic number of nitrogen is 7. The mass is 14.01. This means that a) All nitrogen atoms have exactly 7 neutrons b) A small

adelina 88 [10]

This means that there are 7 protons in the nucleus of a nitrogen atom.

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3 years ago

Read 2 more answers

A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513

igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is: N₂O₄(g) ⇆ 2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

2NO₂ (g) ⇆ N₂O₄(g)

Initially 2.20 mol -

React x x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq (2.20-x) / 3.50L (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) / [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0 → Quadratic formula

a = 0.2933 ; b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50 = 0.0971 M

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Hybridization of NH3​

Hybridization of NH3