We want to solve Q = mcΔT for the liquid water; its change in temperature will tell us the amount of thermal energy that flowed out of the reaction. The specific heat, c, of water is 4.184 J/g °C.
Q = (72.0 g)(4.184 J/g °C)(100 °C - 25 °C) = 22593.6 J
Q ≈ 2.26 × 10⁴ J or 22.6 kJ (three significant figures).
Answer:
No it isn't a dual of nature
Explanation:
If you take the ideal gas law of PV = nRT and modify it to
P*molar mass = density*RT
(745/760)*M = 1.2*0.08206*293
Solve for M = molar mass.
Answer:
Correct option would be A. Mg(s) → Mg2+ + 2e-
Explanation:
Marked as correct answer on Quiz ;) (A P E X)
