Answer:
hello your question has some missing values attached below is the complete question with the missing values
answer :
a) 0.083 secs
b) 0.33 secs
c) 3e^-4/3
Explanation:
Given that
g = 32 ft/s^2 , spring constant ( k ) = 2 Ib/ft
initial displacement = 1 ft above equilibrium
mass = weight / g = 4/32 = 1/8
damping force = instanteous velocity hence β = 1
a<u>)Calculate the time at which the mass passes through the equilibrium position.</u>
time mass passes through equilibrium = 1/12 seconds = 0.083
<u>b) Calculate the time at which the mass attains its extreme displacement </u>
time when mass attains extreme displacement = 1/3 seconds = 0.33 secs
<u>c) What is the position of the mass at this instant</u>
position = 3e^-4/3
attached below is the detailed solution to the given problem
Answer:
Option D, only on the portion of the Earth facing directly toward the Moon
Explanation:
Tides are caused by the gravitational pull of moon. The part of earth that faces the moon experiences the highest gravitational force and hence the high tides will occur in this regions only. The regions that do not faces the moon experiences low tides. It is the gravity of moon that attracts the ocean water towards itself.
Hence, Option D is correct
Answer:
D They have longer seasons
Explanation:
I think this because the days will be longer so that means that the seasons will change also.
Answer:
42.5W
Explanation:
To solve this problem we must go back to the calculations of a weighted average based on the time elapsed thus,
We need to calculate the average power dissipated by the 800\Omega resistor.
Our values are given by:
Aplying the values to the equation we have:
