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serg [7]
2 years ago
8

Power is measured in unit of Joules per second or

Physics
1 answer:
Rasek [7]2 years ago
5 0
D watts yw .yea yww
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Entropy measures disorder and nothing else
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Answer these two questions please
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A soap bubble usually pops because some part of it becomes too thin due to evaporation or drainage of fluid. The change in thick
Lapatulllka [165]

Answer:

To understand why the change in thickness also changes the color of light the bubble reflects, we definitely know that

mλ = dsinθ

when d sin θ = mλ, we expect constructive interference

d = distance between the slits

θ = the angle relative to the incident direction

m = order of the interference

Hence, a change in the thickness will also cause a change in the wavelength, and as wavelength changes, various colors are generated.

The light's path difference is therefore generated as a result of the thickness variation of the soap bubble.

Explanation:

To understand why the change in thickness also changes the color of light the bubble reflects, we definitely know that

mλ = dsinθ

when d sin θ = mλ, we expect constructive interference

d = distance between the slits

θ = the angle relative to the incident direction

m = order of the interference

Hence, a change in the thickness will also cause a change in the wavelength, and as wavelength changes, various colors are generated.

The light's path difference is therefore generated as a result of the thickness variation of the soap bubble.

5 0
2 years ago
What is concave mirror​
Licemer1 [7]

Answer:

A curved mirror is a mirror with a curved reflecting surface. The surface may be either convex or concave. Most curved mirrors have surfaces that are shaped like part of a sphere, but other shapes are sometimes used in optical devices.

Explanation:

8 0
3 years ago
Water is traveling through a horizontal pipe with a speed of 1.7 m/s and at a pressure of 205 kPa. This pipe is reduced to a new
Arturiano [62]

Answer:

The velocity is  v_2 =  6.8 \ m/s

The pressure is  P_2 =  204978 Pa

Explanation:

From the question we are told that

 The speed at which water is travelling through is  v = 1.7 \ m/s

  The pressure is  P_1 = 205  k  Pa =  205 *10^{3} \ Pa

   The diameter of the new pipe is d =  \frac{D}{2}

Where D is the diameter of first pipe

   

According to the principal of continuity we have that

       A_1 v_1 =  A_2 v_2    

Now  A_1 is the area of the first pipe which is mathematically represented as

       A_1 = \pi  \frac{D^2}{4}

and  A_2 is the area of the second pipe which is mathematically represented as  

       A_2 = \pi  \frac{d^2}{4}

Recall   d =  \frac{D}{2}

        A_2 = \pi  \frac{[ D^2]}{4 *4}

        A_2 = \frac{A_1}{4}

So    A_1 v_1 =  \frac{A_1}{4}  v_2

substituting value

        1.7 =  \frac{1}{4}  * v_2    

        v_2 =  4 * 1.7    

       v_2 =  6.8 \ m/s

   

According to Bernoulli's equation  we have that

     P_1 + \rho \frac{v_1 ^2}{2} =  P_2 + \rho \frac{v_2 ^2}{2}

substituting values

     205 *10^{3 }+ \frac{1.7 ^2}{2} =  P_2 +  \frac{6.8 ^2}{2}

     P_2 =  204978 Pa

4 0
2 years ago
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