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2 years ago

Given the arithmetic sequence an = 4 + 8(n − 1), what is the domain for n?

Mathematics

2 answers:

Morgarella [4.7K]2 years ago

6 0

Answer:

n≥1

Step-by-step explanation:

just took test

Svetach [21]2 years ago

3 0

N represents which term
so we can have the 1st, 2nd, 3rd, etc, to the nth term
so n has to be all integers starting with 1 and up
so that would be the option: "All integers where n≥1"

answer is 2nd option

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For every 5 boys, there are 3 girls. If there are 60 students how many boys are there?

adell [148]

Answer:

not solvable

Step-by-step explanation:

so there is a ratio of 5:3

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times 7.5 by 5 and you get 37.5

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8 0

3 years ago

What is the surface area of the cylinder with height 4 km and radius 2 km? Round

saveliy_v [14]

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3 years ago

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vovikov84 [41]

Answer:

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3 years ago

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Shtirlitz [24]

Answer:

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Step-by-step explanation:

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3 years ago

(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$