Answer:
Explanation:
Since the cable touches the road at the mid point of two towers
so here we have vertex at that mid point taken to be origin
now the maximum height on the either side is given as
horizontal distance of the tower from mid point is given as
now from the equation of parabola we have
now we have
now we need to find the height at distance of 200 ft from center
so we have
Answer:
d = 4 d₀o
Explanation:
We can solve this exercise using the relationship between work and the variation of kinetic energy
W = ΔK
In that case as the car stops v_f = 0
the work is
W = -fr d
we substitute
- fr d₀ = 0 - ½ m v₀²
d₀ = ½ m v₀² / fr
now they indicate that the vehicle is coming at twice the speed
v = 2 v₀
using the same expressions we find
d = ½ m (2v₀)² / fr
d = 4 (½ m v₀² / fr)
d = 4 d₀o
The answer is the red sidelight on a powerboat should be visible from the front and from the left (port side).
What are Sidelights?
- There is various combinations of lights that must be used on a boat when it is dark, and these are:
- Sidelights: These lights are called combination lights and are red and green. The red sidelight must be visible from the port side and the green light indicates the right side (the starboard).
- Stern light: The stern light is seen at the back end of the vessel.
- Masthead Light: The masthead light is a white light that shines forwards and on all sides of the vessel. All powered vessels must use this light.
- All-Round white light: This light is the major light that is used to join the masthead light and the stern light. This single light is visible to all vessels from all directions.
- Thus, as a rule for a boat rider, he should show the vision of red light and it should be visible from the front and from the left (port side).
To learn more about Sidelights visit:
brainly.com/question/28205057
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Answer:
<h3>62.5N</h3>
Explanation:
The pressure at one end of the piston is equal to the pressure on the second piston.
Pressure = Force/Area
F1/A1 = F2/A2
Given
F1 = 250N
A1 = 2.0m²
A2 = 0.5m²
F2 = ?
Substituting the given values in the formula;
250/2 = F2/0.5
cross multiply
250*0.5 = 2F2
125 = 2F2
F2 = 125/2
F2 = 62.5N
Hence the force needed to lift this piston if the area of the second piston is 0.5 m^2 is 62.5N
Newton's 3rd law:
Every action has an equal and opposite reaction.
When you apply force on an object, there is an equal force applied on you from that object.
