Convex mirrors only produce virtual images
Answer: Smoke is Abiotic because it is not a living thing.
Explanation: Hopefully this helps u. Have a great rest of your day. I hope this is the right answer
True conditions
Efficiency of Heat Exchanger are as below:
the heat exchange process between two fluids with different temperatures using solid walls occurs in various engineering applications. The tool to achieve this exchange is a heat exchanger. Some applications like air conditioning, power generation, waste heat recovery, and chemical processing use this device.
The basis of the work of a heat exchanger is that the hot fluid enters the heat exchanger at temperature T1 and its heat capacity is Chot. Also, the cold fluid with the heat capacity of Ccold enters temperature t1; in the meantime, the hot fluid loses its heat, and its temperature drops to T2. It delivers heat to the cold fluid to increase its temperature to t2 and leave the heat exchanger at this temperature.
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About 10% to 15% of system charge
Answer:
K = 1.29eV
Explanation:
In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:
(1)
Δx : uncertainty of position = 2.0pm = 2.0*10^-12m
Δp: uncertainty of momentum = ?
h: Planck's constant = 6.626*10^-34 J.s
You calculate the minimum possible value of Δp from the equation (1):
![\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}](https://tex.z-dn.net/?f=%5CDelta%20p%3D%5Cfrac%7Bh%7D%7B4%5Cpi%20%5CDelta%20x%7D%3D%5Cfrac%7B6.626%2A10%5E%7B-34%7DJ.s%7D%7B4%5Cpi%282.0%2A10%5E%7B-12%7Dm%29%7D%5C%5C%5C%5C%5CDelta%20p%3D2.63%2A10%5E%7B-23%7Dkg.%5Cfrac%7Bm%7D%7Bs%7D)
The minimum kinetic energy is calculated by using the following formula:
(2)
m: mass of the proton = 1.67*10^{-27}kg
![k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B%282.63%2A10%5E%7B-23%7Dkgm%2Fs%29%5E2%7D%7B2%281.67%2A10%5E%7B-27%7Dkg%29%7D%3D2.08%2A10%5E%7B-19%7DJ)
in eV you have:
![2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV](https://tex.z-dn.net/?f=2.08%2A10%5E%7B-19%7DJ%2A%5Cfrac%7B6.242%2A10%5E%7B18%7DeV%7D%7B1J%7D%3D1.29eV)
The kinetic energy of the proton is 1.29eV