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Naya [18.7K]
2 years ago
15

Cientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below.

Physics
1 answer:
scZoUnD [109]2 years ago
3 0

Answer:

A few of the positive particles aimed at a gold foil seemed to bounce back.

Explanation:

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if i got an C+ 77% in my science class but i got an 3 F's 0% recently on a science fair project, What will my grade go down to?
Crank
Your grade will probably go down to a D 68% or little higher than that
7 0
3 years ago
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Donde se hizo el “siluetazo”, <br>Me aydan​
brilliants [131]

Answer:

La palabra silueta se deriva del nombre de Étienne de Silhouette, una ministra de finanzas francesa que, en 1759, se vio obligada por la crisis crediticia de Francia durante la Guerra de los Siete Años a imponer severas demandas económicas al pueblo francés, particularmente a los ricos.

Explanation:

3 0
3 years ago
Answer ?
morpeh [17]

Answer:

2.75 m/s^2

Explanation:

The airplane's acceleration on the runway was 2.75 m/s^2

We can find the acceleration by using the equation: a = (v-u)/t

where a is acceleration, v is final velocity, u is initial velocity, and t is time.

In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1

a = 2.75 m/s^2

5 0
2 years ago
List things in your house and put them in order of density
ELEN [110]
I don't know what's in your house! lol. try naming things like: ball, lamp, cup, bowl. 
3 0
3 years ago
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During a compression at a constant pressure of 290 Pa, the volume of an ideal gas decreases from 0.62 m3 to 0.21 m3. The initial
Aloiza [94]

Answer:

a) -41.1 Joule

b) 108.38 Kelvin

Explanation:

Pressure = P = 290 Pa

Initial volume of gas = V₁ = 0.62 m³

Final volume of gas = V₂ = 0.21 m³

Initial temperature of gas = T₁ = 320 K

Heat loss = Q = -160 J

Work done = PΔV

⇒Work done = 290×(0.21-0.62)

⇒Work done = -118.9 J

a) Change in internal energy = Heat - Work

ΔU = -160 -(-118.9)

⇒ΔU = -41.1 J

∴ Change in internal energy is -41.1 J

b) V₁/V₂ = T₁/T₂

⇒T₂ = T₁V₂/V₁

⇒T₂ = 320×0.21/0.62

⇒T₂ = 108.38 K

∴ Final temperature of the gas is 108.38 Kelvin

5 0
3 years ago
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