I believe the answer is carbon atoms
Answer:
1. Molecular equation
BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)
2. Complete Ionic equation
Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)
3. Net ionic equation
Cl¯(aq) + Ag⁺(aq) —> AgCl(s)
Explanation:
Answer:
100ml of a stock 50% KNO3 solutions are needed to prepare 250ml of a 20% KNO3 solution.
Explanation:
In the given question it is mentioned that
S1=50%
V2=250ml
S2= 20%
We all know that
V1S1=V2S2
∴V1= V2×S2÷S1
∴V1= V2S2×1/S1
∴V1= 250×20÷50
∴V1= 100ml
Is this multi choice or no?
Answer:
a). Coordination no. of
= 6
b). Coordination no. of
= 6
Explanation:
Coordination number is defined as number of donar atoms bonded to the central atom of the complex ion.
a). Coordination no. of
= 6
en or ethylenediamine is a bidentate ligand.
In bidentate ligand, two atoms directly bonded to the central atom.
NH3 is a unidentate ligand.
So, coordination no.= No. of bidentate ligand x 2 + No. of unidentate ligand
= 
b). Coordination no. of
= 6
Ethylenediamine (en) is a bidentate ligand.
oxalate ion (ox) is also a bidentate ligand.
Cl is a unidentate ligand
So, coordination no.= No. of bidentate ligand x 2 + No. of unidentate ligand
= 