Answer
Given,
Sound Power, P = 600 W
a) Intensity of sound,
r = 5 m
we know,
I = 1.91 W/m²
b) Sound intensity
I₀ = 10⁻¹²
c) Sound experienced by the Phil
β₁ = 123 - 23 = 100 \ dB
distance from the sound
again using sound intensity formula
where, I = P/A
r = 69.09 m
Distance where Phil will experience same sound intensity without earplug is equal to r = 69.09 m
Answer:
Omg tysm you are too kind
Explanation:
It is how forces affect nature
Answer:
Explanation:
Given:
- wavelength of light in the air,
- time taken to travel from the source to the photocell via air,
- time taken to reach the photocell via air and glass slab,
- thickness of the glass slab,
<u>Now we have the relation for time:</u>
hence,
c= speed of light in air
For the case when glass slab is inserted between the path of light:
(since light travel with the speed c only in the air)
here:
v = speed of light in the glass
Using Snell's law:
Answer:
Jun 29, 2016 · Tectonic plates are large segments of the Earth’s crust that move slowly. Suppose that one such plate has an average speed of 4.0 cm/year. (a) What distance does it move in 1.0 s at this speed? (b) What is its speed in kilometers per million years?
Explanation: