Answer:
Explanation:
Because of the following ,it is useful to select both objects as the system during collision between an electron and a hydrogen atom
1. The total momentum of the system does not change during the collision.
2.The forces the objects exert on each other are internal to the system and don't change the total momentum of the system.
3. During the time interval just before to just after the collision, external forces are negligible.
Explanation:
Q=mc(T2-T1)
or
q = mcΔT ,
where m is the mass of the sample,
c is the specific heat,
and ΔT is the temperature change.
Q=2.0 × 2000 × 5
Q=20000J⋅kg −1 ⋅K −1
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For this problem, we will need the famous equation F=ma, as detailed by Isaac Newton.
F=mass x acceleration, where Force is in Newtons.
20 m/s represents the quantity of speed change, but to use in the equation, we need acceleration, not speed. Acceleration is the velocity change over a unit time, so changing 20 m/s in 0.1 seconds means that the acceleration was 200 m/s^2.
Plugging in all your numbers, you find:
F=(0.45 kg)(200 m/s^2) = 90 N of force.
Answer:
weigh is 2353.13 N
Explanation:
Given data
density = 7890.00 kg/m3
lighter = 299 N
to find out
the volume of the anchor and weigh in air
solution
from question we can say that
apparent weight = actual weight - buoyant force
we know weight = mg and buoyant force = water density × g
so volume of anchor is = actual weight - apparent weight / buoyant force
volume of anchor is = 299 / 1000 × 9.81
volume of anchor is = 0.0304791 m³
and
weight of anchor is mg
here mass m = density Fe g
density Fe = 7870 from table 14-1
so weight = 7870 × 0.0304791 × 9.81
weigh is 2353.13 N
