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3 years ago

Why do we see different colors of white light if white light is what is shining down from the sun?

Physics

2 answers:

yanalaym [24]3 years ago

8 0

Answer:

the earth spins around the sun

Explanation:

oee [108]3 years ago

5 0

Answer:Hope this helped.

Explanation:

Because each color is refracted differently, each bends at a different angle, resulting in a fanning out and separation of white light into the colors of the spectrum. Water droplets in the air can act in a manner similar to that of a prism, separating the colors of sunlight to produce a spectrum known as a rainbow.────(♥)(♥)(♥)────(♥)(♥)(♥) __ ɪƒ ƴσυ'ʀє αʟσηє,

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──(♥)████████████████(♥) ɪƒ ƴσυ ѡαηт α ɧυɢ,

────(♥)████████████(♥) __ ɪ'ʟʟ ɓє ƴσυʀ ρɪʟʟσѡ.

──────(♥)████████(♥) ɪƒ ƴσυ ηєє∂ тσ ɓє ɧαρρƴ,

────────(♥)████(♥) __ ɪ'ʟʟ ɓє ƴσυʀ ѕɱɪʟє.

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───────────(♥) __ ɪ'ʟʟ ʝυѕт ɓє ɱє.

You might be interested in

The more twists per foot in a pair of wires, the more resistant the pair will be to ____.

Murljashka [212]

The more twist per foot in a pair of wires, the more resistant the pair will be to cross talk. A cross talk in network planning and design is a disturbance produced by electromagnetic interference beside a circuit or a cable pair. A telecommunication signal interrupts a signal in an adjacent circuit and can source the signals to turn out to be confused and cross over each other.

6 0

3 years ago

If an astronomer wants to find and identify as many stars as possible in a star cluster that has recently formed near the surfac

Andru [333]

Answer:

Infrared telescope and camera

Explanation:

An infrared telescope uses infrared light to detect celestial bodies. The infrared radiation is one of the known forms of electromagnetic radiation. Infrared radiation is given off by a body possessing some form of heat. All bodies above the absolute zero temperature in the universe radiates some form of heat, which can then be detected by an infrared telescope, and infrared radiation can be used to study or look into a system that is void of detectable visible light.

Stars are celestial bodies that are constantly radiating heat. In order to see a clearer picture of the these bodies, Infrared images is better used, since they are able to penetrate the surrounding clouds of dust, and have located many more stellar components than any other types of telescope, especially in dusty regions of star clusters like the Trapezium cluster.

5 0

2 years ago

Find the velocity of a baseball thrown 78 m from third base to first base in 30 sec

ankoles [38]

Answer:

V=2.6m/s

Explanation:

velocity=Distance/time

V=78/30=2.6m/s

3 0

2 years ago

Your roommate is working on his bicycle and has the bike upside down. He spins the 60 cm

tigry1 [53]

Diameter = 60 cm, Radius = 60/2 = 30 cm = 30/100 = 0.3 m.

The pebble in the tread goes by 3 times every second.

This is the same as 3 times per second.

Recall the unit of frequency is Hertz or per second, s⁻¹

So 3 times per second, Frequency, f = 3s⁻¹ or 3 Hertz

For angular motion:

Angular speed, ω = 2πf

   = 2*π*3

   = 6π   rad/s

Linear speed, v = ωr = 6π * 0.3 = 1.8π m/s

Linear acceleration, a = v² / r

   a = 1.8π * 1.8π / 0.3 = 10.8π² m/s²

Angular acceleration α = a/r = 10.8π² / 0.3 = 36π² rad/s²

Angular speed = 6π rad/s ≈ 18.840 rad/s

The linear speed of the pebble = 1.8π m/s ≈ 5.655 m/s

The angular acceleration = 36π² rad/s² ≈ 355.306 rad/s²

The linear acceleration of the pebble = 10.8π² m/s ≈ 106.592 m/s²

5 0

3 years ago

A gas occupies 2 m^3 at 27°C at a pressure of 1 atmosphere. At a pressure of 2 atmospheres it occupies a volume of 1 m^2. What i

diamong [38]

Answer:

27°C

Explanation:

We'll begin by converting 27 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 27 °C

Initial temperature (T₁) = 27 °C + 273

Initial temperature (T₁) = 300 K

Next, we shall determine the final temperature of the gas. This can be obtained as follow:

Initial volume (V₁) = 2 m³

Initial temperature (T₁) = 300 K

Initial pressure (P₁) = 1 atm

Final pressure (P₂) = 2 atm

Final volume (V₂) = 1 m³

Final temperature (T₂) =?

P₁V₁/T₁ = P₂V₂/T₂

1 × 2 / 300 = 2 × 1 / T₂

2/300 = 2/T₂

1/150 = 2/T₂

Cross multiply

T₂ = 150 × 2

T₂ = 300 K

Finally, we shall convert 300 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 300 K

T(°C) = 300 – 273

T(°C) = 27°C

Thus, the final temperature is 27°C

6 0

2 years ago