A 10 kg mass rests on a table. What acceleration will be generated when a force of 20 N is applied and encounters a frictional f
1 answer:
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Answer:
35
Explanation:
We are given that
Initial voltage,
Final voltage,
Number of tuns in primary coil of the transformer,
Rms current,
We have to find the number of turns are there on the secondary coil.
We know that
Using the formula
Hence, there are number of turns on the secondary coil=35
The object’s resultant angle of motion with the +x-axis after the collision is 47°
<span>From object A:
1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.
Now, we know, tan</span>Ф =
⇒tanФ =
⇒tanФ = 1.088
⇒ Ф =
1.088
= 47.4 ≈ 47
<span>From object A:
1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.
Now, we know, tan</span>Ф =
⇒tanФ =
⇒tanФ = 1.088
⇒ Ф =
= 47.4 ≈ 47