A 10 kg mass rests on a table. What acceleration will be generated when a force of 20 N is applied and encounters a frictional f
1 answer:
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Answer:
Explanation:
Given data
Q₁=200cm³/s
We know that:
can be written as:
ΔP=F/A=n×v/L
And
Q=ΔP/R
As
n₂=6.0n₁
So
Q=ΔP/R
Answer:
upward force acting = 261.6 N
Explanation:
given,
mass of gibbon = 9.4 kg
arm length = 0.6 m
speed of the swing
net force must provide
force of gravity = - mg
=
=
=9 x 29.067
= 261.6 N
upward force acting = 261.6 N