A three-point flexure test is conducted on a cylindrical specimen of aluminum oxide. The specimen radius is 5.0 mm and the dista
nce between the two supportsis 15.0 mm. If the specimen breaks when the applied force is 7500 N and the center deflection is 0.01 mm, what are the elastic modulus andthe flexural strength of the material?
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Answer:
The required bulk modulus is Psi. So, the answer is non of these.
Explanation:
Change in pressure of the fluid is directly proportional to the volumetric strain. The constant of proportionality is the bulk modulus of the fluid.
Step1
Given:
Percentage change in volume is 1%.
Change in pressure is 10000 Psi.
Calculation:
Step2
Volumetric strain is calculated as follows:
Step3
Bulk modulus is calculated as follows:
\frac{\bigtriangleup V}{V}=0.01
K = 1000000 Psi.
Thus, the required bulk modulus is Psi.
Answer:
See the attached file for the answers.
Explanation:
Find attached of the explanation
