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LuckyWell [14K]
3 years ago
5

An object of mass 0.5 kg is swung in uniform circular motion. The radius is 2 meters, and the force exerted is 4 N. Calculate th

e magnitude of the velocity.
Physics
1 answer:
Katarina [22]3 years ago
8 0
Using
F= mv²/r
4 = 0.5×v² / 2
8 /0.5 = v²
v²=16
v= √16
v= 4 ms-¹
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Answer:

Explanation:

She's correct but doesn't mean the wagon cannot put into motion. The force that she applied on the wagon, according to Newton's 2nd law, would have generated an acceleration, which translates into motion. The reaction force the wagon applies on her due to Newton's 3rd law, would not hinder its own motion.

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3 years ago
The alarm at a fire station rings and a 87.5-kg fireman, starting from rest, slides down a pole to the floor below (a distance o
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Answer:

F_f=840N

Explanation:

From the question we are told that

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v^2 = v_0^2 + 2 a d

Therefore Acceleration a

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a'= 0.21m/s^2

Generally the equation for Frictional force F_f is mathematically given as

F_f=m*a

F_f=m*(g-0.21)

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6 0
3 years ago
Why is acceleration of an object moving at a constant velocity always zero?
k0ka [10]

Answer:

If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).

Explanation:

In the middle, when the object was changing position at a constant velocity, the acceleration was 0. This is because the object is no longer changing its velocity and is moving at a constant rate.

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True

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Lilit [14]

hey guy

the vibration per second is frequency

then for 20 vibration time taken is 100 second

in 1 second 20/100 vibration took place

it means 0.2 is frequency

for time period , we have

t=1/f

=1/0.2

=5

8 0
3 years ago
Read 2 more answers
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