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GREYUIT [131]
3 years ago
15

NIST 800-14's Principles for Securing Information Technology Systems, can be used to make sure the needed key elements of a succ

essful effort are factored into the design of an information security program and to produce a blueprint for an effective security architecture.a) trueb) false
Physics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

True

Explanation:

-NIST 800-14's are generally accepted principles for securing information technology systems.

- The defined principles, if adhered to and continously improved, will will ensure sytem security over it's lifetime as desired.

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The unit of area is a derived unit. Why?
prohojiy [21]

Explanation:

area=length(m) ×breadth(m) . The unit of area is expressed in terms of fundamental units m^2.thus it is derived unit

8 0
3 years ago
if length of the spring is doubled, what will happen to its time period? if mass of the spring is doubled and spring constant wi
melamori03 [73]

If the length of the spring is doubled, there will be no effect on its period.

If the mass of the spring is doubled and the spring constant is halved, then its period will be doubled.

The Simple Harmonic Motion is a type of periodic motion and one of its examples is the spring-mass system.

The period of a spring mass system is given by the following equation,

T= 2π√m/√k

Here, T= period of spring

m= Mass of the body attached to the spring

k= Spring constant

According to the above equation, the period of a spring depends on the mass of the body and the spring constant.

It is independent of the length of the spring.

Therefore, if the length of spring is doubled then there will be no effect on its period.

If the mass of spring is doubled and the spring constant is halved, then the equation becomes

T'= 2π√2m/√k/2

T'= √4 x 2π√m/√k

T'= 2 x T

Hence, if the mass of the spring is doubled and the spring constant is halved, its period will be doubled.

To know more about the "spring-mass system", refer to the following link:

brainly.com/question/13156044?referrer=searchResults

#SPJ4

5 0
2 years ago
A long, hollow, cylindrical conductor (with inner radius 2.0 mm and outer radius 4.0 mm) carries a current of 24 A distributed u
tigry1 [53]

Answer:

a) 0.0048 T

b) 0.00093 T

c) 0 T

Explanation:

B = μ(0) [I - i'] / 2πr

where I = 24, and i' = 0, this means that

B = [12.568*10^-7 (24 - 0) ] / 2 * 3.142 * 0.001

B = 3.016*10^-5 / 0.006284

B = 0.0048 T

b), formula is the same, except for change in values, so we have

I = 24, and

i' = (3y2 - 2y2) / (4y2 - 2y2) * 24

i' = 10, and substituting these in the equation, we have

B = [12.568*10^-7 (24 - 10) ] / 2 * 3.142 * 0.003

B = (12.568*10^-7 * 14) / 0.018852

B = 1.76*10^-5 / 0.018852

B = 0.00093 T

and for the last one, we have

I = 24 and i' = 24 also, so that

B = [12.568*10^-7 (24 - 24) ] / 2 * 3.142 * 0.005

B = 0 / 0.03142

B = 0

3 0
3 years ago
Which of the following foods are rich in protein:
Vedmedyk [2.9K]
Avocado and cottage cheese are both proteins.

3 0
3 years ago
Read 2 more answers
A wire has a resistance of 27.2 ohms. It is melted down, and from the same volume of metal a new wire is made that is 3 times lo
solmaris [256]

Answer:

81.6 ohm

Explanation:

For a cable type conductor, the resistance is given by the following formula:

R=\rho \frac{l}{S}

Where:

\rho=Material\hspace{3}resistivity\\l=Cable\hspace{3}length\\S=Cable\hspace{3}cross\hspace{3}section

The problem doesn't give us additional information about resistivity or the cross section of the wire, so let's assume:

S=constant\\\rho=constant

Then, in this case, the resistance of the cable depends only on the length. Therefore, if its resistance was originally 27.2 ohms, if we triple its length, it makes sense that its new resistance is three times the original. Thus:

R=3*(27.2)=81.6ohm

5 0
3 years ago
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