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Lilit [14]
3 years ago
7

Please help me answer this question! Will appreciate help very much. a) Draw a circuit to show 3 lights in series b) Draw a circ

uit to show 2 lights in parallel c) Draw a circuit that shows 2 lights in parallel which are both in series with a third light. d) What would happen to the 2 other lights if the third light in question c) fails
Physics
1 answer:
Scorpion4ik [409]3 years ago
3 0

Answer:

C kind sir

Explanation:

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Please I really need help on these
blagie [28]

Answer:

  3, 4, 2

Explanation:

I can't see the final ones.

4 0
3 years ago
A two-dimensional section of the body is known as an
lesya692 [45]
Median plane ..........
7 0
3 years ago
A bullet is fired through a wooden board with a thickness of 9.0 cm. The bullet hits the board perpendicular to it, and with a s
gtnhenbr [62]

Answer:

-387883.3 m/s²

0.000286168546055 seconds

Explanation:

t = Time taken

u = Initial velocity = 370 m/s

v = Final velocity = 259 m/s

s = Displacement = 9 cm

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{259^2-370^2}{2\times 9\times 10^{-2}}\\\Rightarrow a=-387883.3\ m/s^2

The acceleration of the bullet is -387883.3 m/s²

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{259-370}{-387883.3}\\\Rightarrow t=0.000286168546055\ s

The time taken is 0.000286168546055 seconds

4 0
4 years ago
4.A 31-cm long conducting wire of 9-g carrying 7- A current is placed in a uniform magnetic field. What are the strength and dir
Anika [276]

Answer

Given,

Length of the wire,L = 31 cm = 0.31 m

mass of the wire, m = 9 g = 0.009 Kg

Current in the wire,I = 7 A

Magnetic field strength, B= ?

Equating magnetic force to the weight of the wire.

BIL = m g

B=\dfrac{m g}{IL}

B=\dfrac{0.009\times 9.81}{7\times 0.31}

B = 0.0407 T

For Force to be upward magnetic field direction should be outward of the plane of paper.

7 0
3 years ago
A grocery cart with a mass of 15 kg is being pushed at constant speed up a 12∘ ramp by a force FP which acts at an angle of 17∘
Alenkasestr [34]

Answer: a. 198.6J b. - 198.6J

Explanation: Parameters given:

m = 15kg

g = 9.8m/s²

∅ = 12°

a. Work done by the force Fp on the cart if the ramp is 6.5m long.

Given the formula, Fp = Mgsin∅ = 15 x 9.8 x sin12° = 30.56N

Therefore Work done (Wp) = Fp x Ramp Length = 30.56 x 6.5 = 198.64Nm or 198.6J

b. The work done by the force mg on the cart.

Since the cart is being pushed upwards, it acts against gravity with its direction of motion. Taking into account the formula from the previous answer for Work Done (Wg) = Fmg x distance

= 15kg x -9.8m/s² x Sin12° x 6.5m

= - 198.6J

4 0
3 years ago
Read 2 more answers
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