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Ludmilka [50]
3 years ago
8

The least common multiple of 15 and 20 is k. What is the least common multiple of 12 and k?

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
5 0
I think it could be 1 but I'm not sure sorry
dedylja [7]3 years ago
3 0
I THINK the answer is 5 I'm really sorry if I'm wrong
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What is 0.888 into a fraction, is it over 100ths or 1,000's?
Bingel [31]

Thanks for using Brainly!

0.888 = 111/125 = 88.8percent

I just gave you 0.888 is it's fraction and percentage.

First, 111/125 is the simplified answer and is over the 100th and is not big enough for the 1,000's.

Second, 111/125 as a percentage is 88.8%.

Have a great day.

8 0
3 years ago
Prove A-(BnC) = (A-B)U(A-C), explain with an example​
NikAS [45]

Answer:

Prove set equality by showing that for any element x, x \in (A \backslash (B \cap C)) if and only if x \in ((A \backslash B) \cup (A \backslash C)).

Example:

A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace.

B = \lbrace0,\, 1 \rbrace.

C = \lbrace0,\, 2 \rbrace.

\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}.

\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}.

Step-by-step explanation:

Proof for [x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))] for any element x:

Assume that x \in (A \backslash (B \cap C)). Thus, x \in A and x \not \in (B \cap C).

Since x \not \in (B \cap C), either x \not \in B or x \not \in C (or both.)

  • If x \not \in B, then combined with x \in A, x \in (A \backslash B).
  • Similarly, if x \not \in C, then combined with x \in A, x \in (A \backslash C).

Thus, either x \in (A \backslash B) or x \in (A \backslash C) (or both.)

Therefore, x \in ((A \backslash B) \cup (A \backslash C)) as required.

Proof for [x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]:

Assume that x \in ((A \backslash B) \cup (A \backslash C)). Thus, either x \in (A \backslash B) or x \in (A \backslash C) (or both.)

  • If x \in (A \backslash B), then x \in A and x \not \in B. Notice that (x \not \in B) \implies (x \not \in (B \cap C)) since the contrapositive of that statement, (x \in (B \cap C)) \implies (x \in B), is true. Therefore, x \not \in (B \cap C) and thus x \in A \backslash (B \cap C).
  • Otherwise, if x \in A \backslash C, then x \in A and x \not \in C. Similarly, x \not \in C \! implies x \not \in (B \cap C). Therefore, x \in A \backslash (B \cap C).

Either way, x \in A \backslash (B \cap C).

Therefore, x \in ((A \backslash B) \cup (A \backslash C)) implies x \in A \backslash (B \cap C), as required.

8 0
2 years ago
What does the expression 5-n mean
Novay_Z [31]

Answer:

It just means "5-n"

Step-by-step explanation:

There's really nothing to it. It's just an expression, it doesn't 'mean' anything.

4 0
3 years ago
Find the difference between -14w - 3 and 5w
Alexus [3.1K]

Answer:

-19w-3

Step-by-step explanation:

-5w from

-14w-3

-19w-3

6 0
2 years ago
A right square pyramid has a slant height of 25 feet, and the length of a side
Amanda [17]

Answer:

C. 24 ft.

Step-by-step explanation:

There is a right triangle which can be drawn in side the pyramid with height h, hypotenuse  25 ft and bas = 1/2 * 14 = 7.

So using Pythagoras:

25^2 = h^2 + 7^2

h^2 = 25^2 - 7^2

h^2 = 576

h = √576 = 24 ft.

8 0
3 years ago
Read 2 more answers
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