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Tcecarenko [31]
3 years ago
13

Which statements can be supported by using a position-time graph? Check all that apply. A negative slope results when an individ

ual is moving toward the origin. A horizontal line on the graph means the individual is moving at the same velocity. A positive slope results when an individual is moving away from the origin. The slope of the line gives the velocity of the individual. The speed of an individual cannot be determined from this type of graph.
Physics
2 answers:
Naya [18.7K]3 years ago
8 0

A negative slope results when an individual is moving toward the origin.

A positive slope results when an individual is moving away from the origin.

The slope of the line gives the velocity of the individual.

Explanation:

In a position-time graph, the position is represented on the y-axis (distance from the origin), while the time is represented on the x-axis. Let's analyze each statement:

A negative slope results when an individual is moving toward the origin. --> TRUE. In fact, a negative slope means that the value on the y is decreasing as the time passes, so the distance of the individual is decreasing as the time increases, therefore the person is moving towards the origin.

A horizontal line on the graph means the individual is moving at the same velocity. --> FALSE. A horizontal line means that the position of the individual is constant, so the person is not moving.

A positive slope results when an individual is moving away from the origin. --> TRUE. In this case, the value on the y is increasing with time, so the distance of the person from the origin is increasing with time.

The slope of the line gives the velocity of the individual. --> TRUE. In a position-time graph, the velocity of the individual is equal to the ratio between the displacement and the time taken. But the displacement corresponds to the increase in the y-value, while the time corresponds to the increase in the x-value, so the velocity corresponds to the slope of the graph. In order to know velocity, we must also know the direction of the motion.

The speed of an individual cannot be determined from this type of graph. --> FALSE. The speed is equal to the slope of the position-time graph (in fact, the speed is the magnitude of the velocity)

Mademuasel [1]3 years ago
7 0

Answer:

A negative slope results when an individual is moving toward the origin.

A positive slope results when an individual is moving away from the origin.

The slope of the line gives the velocity of the individual.

Explanation:

Just took the quiz on ed

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tia_tia [17]

The distance travelled by the ball that is thrown horizontally from a window that is 15.4 meters high at a speed of 3.01 m/s is 5.34 m

s = ut + 1 / 2 at²

s = Distance

u = Initial velocity

t = Time

a = Acceleration

Vertically,

s = 15.4 m

u = 0

a = 9.8 m / s²

15.4 = 0 + ( 1 / 2 * 9.8 * t² )

t² = 3.14

t = 1.77 s

Horizontally,

u = 3.01 m / s

a = 0 ( Since there is no external force )

s = ( 3.01 * 1.77 ) + 0

s = 5.34 m

Therefore, the distance travelled by the ball before hitting the ground is 5.34 m

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1 year ago
When a voltage difference is applied to a piece of metal wire, a 5.0 mA current flows through it. If this metal wire is now repl
zheka24 [161]

Answer:

I = 21.13 mA ≈ 21 mA

Explanation:

If

I₁ = 5 mA

L₁ = L₂ = L

V₁ = V₂ = V

ρ₁ = 1.68*10⁻⁸ Ohm-m

ρ₂ = 1.59*10⁻⁸ Ohm-m

D₁ = D

D₂ = 2D

S₁ = 0.25*π*D²

S₂ = 0.25*π*(2*D)² = π*D²

If we apply the equation

R = ρ*L / S

where (using Ohm's Law):

R = V / I

we have

V / I = ρ*L / S

If V and L are the same

V / L =  ρ*I / S

then

(V / L)₁ = (V / L)₂  ⇒     ρ₁*I₁ / S₁ = ρ₂*I₂ / S₂

If

S₁ = 0.25*π*D²   and

S₂ = 0.25*π*(2*D)² = π*D²

we have

ρ₁*I₁ / (0.25*π*D²) = ρ₂*I₂ / (π*D²)

⇒    I₂ = 4*ρ₁*I₁ / ρ₂

⇒     I₂ = 4*1.68*10⁻⁸ Ohm-m*5 mA / 1.59*10⁻⁸ Ohm-m

⇒     I₂ = 21.13 mA

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3 years ago
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Answer:

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Explanation:

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2 years ago
The platform height for Olympic divers is 10 m. A 60 kg diver steps off the platform to begin his dive.
azamat

Answer:

a) Ep = 5886[J]; b) v = 14[m/s]; c)   W = 5886[J]; d) F = 1763.4[N]

Explanation:

a)

The potential energy can be found using the following expression, we will take the ground level as the reference point where the potential energy is equal to zero.

E_{p} =m*g*h\\where:\\m = mass = 60[kg]\\g = gravity = 9.81[m/s^2]\\h = elevation = 10 [m]\\E_{p}=60*9.81*10\\E_{p}=5886[J]

b)

Since energy is conserved, that is, potential energy is transformed into kinetic energy, the moment the harpsichord touches water, all potential energy is transformed into kinetic energy.

E_{p} = E_{k} \\5886 =0.5*m*v^{2} \\v = \sqrt{\frac{5886}{0.5*60} }\\v = 14[m/s]

c)

The work is equal to

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d)

We need to use the following equation and find the deceleration of the diver at the moment when he stops his velocity is zero.

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By performing a sum of forces equal to the product of mass by acceleration (newton's second law), we can find the force that acts to reduce the speed of the diver to zero.

m*g - F = m*a

F = m*a - m*g

F = (60*39.2) - (60*9.81)

F = 1763.4 [N]

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3 years ago
What happens to gravity when someone jumps up?
Alla [95]

Answer:

The direct answer to the question as written is as follows: nothing happens to gravity when someone jumps up - gravity continues exerting a force on the body of that particular someone proportional to (mass of someone) x (mass of Earth) / (distance squared). What you might be asking, however, is what is the net force acting on the body of someone jumping up. At the moment of  someone jumping up there is an upward acceleration, i.e., an upward-directed force which counteracts the gravitational force - this is the net force ( a result of the jump force minus gravity). From that moment on, only gravity acts on the body. The someone moves upward gradually decelerating to the downward gravitational acceleration until they reaches the peak of the jump (zero velocity). Then, back to Earth.


5 0
3 years ago
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