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Tcecarenko [31]
3 years ago
13

Which statements can be supported by using a position-time graph? Check all that apply. A negative slope results when an individ

ual is moving toward the origin. A horizontal line on the graph means the individual is moving at the same velocity. A positive slope results when an individual is moving away from the origin. The slope of the line gives the velocity of the individual. The speed of an individual cannot be determined from this type of graph.
Physics
2 answers:
Naya [18.7K]3 years ago
8 0

A negative slope results when an individual is moving toward the origin.

A positive slope results when an individual is moving away from the origin.

The slope of the line gives the velocity of the individual.

Explanation:

In a position-time graph, the position is represented on the y-axis (distance from the origin), while the time is represented on the x-axis. Let's analyze each statement:

A negative slope results when an individual is moving toward the origin. --> TRUE. In fact, a negative slope means that the value on the y is decreasing as the time passes, so the distance of the individual is decreasing as the time increases, therefore the person is moving towards the origin.

A horizontal line on the graph means the individual is moving at the same velocity. --> FALSE. A horizontal line means that the position of the individual is constant, so the person is not moving.

A positive slope results when an individual is moving away from the origin. --> TRUE. In this case, the value on the y is increasing with time, so the distance of the person from the origin is increasing with time.

The slope of the line gives the velocity of the individual. --> TRUE. In a position-time graph, the velocity of the individual is equal to the ratio between the displacement and the time taken. But the displacement corresponds to the increase in the y-value, while the time corresponds to the increase in the x-value, so the velocity corresponds to the slope of the graph. In order to know velocity, we must also know the direction of the motion.

The speed of an individual cannot be determined from this type of graph. --> FALSE. The speed is equal to the slope of the position-time graph (in fact, the speed is the magnitude of the velocity)

Mademuasel [1]3 years ago
7 0

Answer:

A negative slope results when an individual is moving toward the origin.

A positive slope results when an individual is moving away from the origin.

The slope of the line gives the velocity of the individual.

Explanation:

Just took the quiz on ed

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A 70.0 kg sprinter starts a race with an acceleration of 1.60 m/s^2, What is the net external force (in N) on him? (Enter the ma
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External force on him will be 112 N

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OlgaM077 [116]

Here is the rule for see-saws here on Earth, and there is no reason
to expect that it doesn't work exactly the same anywhere else:

                     (weight) x (distance from the pivot) <u>on one side</u>
is equal to
                     (weight) x (distance from the pivot) <u>on the other side</u>.

That's why, when Dad and Tiny Tommy get on the see-saw, Dad sits
closer to the pivot and Tiny Tommy sits farther away from it.

       (Dad's weight) x (short length) = (Tiny Tommy's weight) x (longer length).


So now we come to the strange beings on the alien planet.
There are three choices right away that both work:

<u>#1).</u>
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       (400) x (1)  =    (200) x (2)

<u>#2).</u>
(200 N) in the middle-seat, facing (100 N) in the end-seat.

       (200) x (1)  =    (100) x (2)

<u>#3).</u>

On one side:  (300 N) in the end-seat       (300) x (2) = <u>600</u>

On the other side:
                      (400 N) in the middle-seat  (400) x (1) = 400
           and     (100 N) in the end-seat      (100) x (2) = 200
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These are the only ones to be identified at Harvard . . . . . . .
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5 0
3 years ago
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Robert has just bought a new model rocket, and is trying to measure its flight characteristics. The rocket engine package claims
777dan777 [17]

Answer:

The work done by the drag force is given by 29.96 J

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From work energy theorem,

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Where W_{t} = thrust work W_{g} = gravitational work

KE = 12.3 \times 10.2 -Wd - 0.663 \times 9.8 \times 10.2

KE = 59.2 -Wd

After cutoff kinetic energy is converted into potential energy,

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Put value of KE

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Work done by drag force is given by,

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Therefore, the work done by the drag force is given by 29.96 J

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