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WITCHER [35]
3 years ago
14

What object circles around a planet

Physics
2 answers:
agasfer [191]3 years ago
4 0
A object that circles around a planet is called a satellite.<span />
kirill115 [55]3 years ago
3 0
An object that circles around a planet is a satellite. earth's satellite is the moon.
<span />
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To determine the muzzle velocity of a bullet fired from a rifle, you shoot the 2.47-g bullet into a 2.43-kg wooden block. The bl
Elza [17]

Answer:

The velocity of the bullet on leaving the gun's barrel is 236.36 m/s.

Explanation:

Given;

mass of the bullet, m₁ = 2.47 g = 0.00247 kg

mass of the wooden block, m₂ = 2.43 kg

initial velocity of the wooden block, u₂ = 0

height reached by the bullet-block system after collision = 0.295 cm = 0.00295 m

let the initial velocity of the bullet on leaving the gun's barrel = v₁

let final velocity of the bullet-wooden block system after collision = v₂

Apply the principle of conservation of linear momentum;

Total initial momentum = Total final momentum

m₁v₁ + m₂u₂ = v₂(m₁ + m₂)

0.00247v₁  + 2.43 x 0  =  v₂(2.43 + 0.00247)

0.00247v₁ = 2.4325v₂ -------(1)

The kinetic energy of the bullet-block system after collision;

K.E = ¹/₂(m₁ + m₂)v₂²

K.E = ¹/₂ (2.4325)v₂²

The potential energy of the bullet-block system after collision;

P.E = mgh

P.E = (2.4325)(9.8)(0.00295)

P.E = 0.07032

Apply the principle of conservation of mechanical energy;

K.E = P.E

¹/₂ (2.4325)v₂² = 0.07032

1.21625 v₂²  = 0.07032

v₂²  = 0.07032  / 1.21625

v₂² = 0.0578

v₂ = √0.0578

v₂ = 0.24 m/s

Substitute v₂ in equation (1), to obtain the initial velocity of the bullet;

0.00247v₁ = 2.4325v₂

0.00247v₁ = 2.4325 (0.24)

0.00247v₁ = 0.5838

v₁ = 0.5838 / 0.00247

v₁ = 236.36 m/s

Therefore, the velocity of the bullet on leaving the gun's barrel is 236.36 m/s.

5 0
3 years ago
1. What is the difference between longitudinal and transverse waves? Compare and contrast
Anvisha [2.4K]

Answer: image to much to type.

Explanation:

8 0
3 years ago
A coil of wire is comprised of 5 turns, has a current of 2 mA running through it, and a net magnetic field at its center of B is
VARVARA [1.3K]

Answer:

<em>20cm</em>

Explanation:

<em>A coil wire comprises of 5 turns,  it has a current of 2mA </em>

<em>A net magnetic field at the center of B is equal to Mu over 40 end fractions times T</em>

<em>The radius of a coil of wire with N turns is r = 0.28 m. A clockwise current of Icoil = 1.0 A flows in the coil,</em>

<em>Therefore 40/2mA = 20</em>

6 0
3 years ago
Like pole of magnet ----------each other ​
Lady_Fox [76]

Answer:

repeal each other......

8 0
2 years ago
A satellite is orbiting Earth in an approximately circular path. It completes one revolution each day (86,400 seconds). Its orbi
Dafna1 [17]

For each revolution, the satellite covers the circumference
of its orbit.

The circumference of a circle is    (pi) x (diameter).

Since the satellite is 22,500 miles from the center, that number
is the radius of the circle.  The diameter is  45,000 miles.

The circumference is    (pi) x (45,000 miles) = 141,372 miles
                                                                        
The satellite's average speed is  141,372 miles per day, or

       (141,372 / 24) = 5,890 miles per hour

relative to the center of the Earth.



5 0
3 years ago
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