A string under a tension of 50.4 N is used to whirl a rock in a horizontal circle of radius 2.51 m at a speed of 21.1 m/s. The s
1 answer:
Answer:
619.8 N
Explanation:
The tension in the string provides the centripetal force that keeps the rock in circular motion, so we can write:
where
T is the tension
m is the mass of the rock
v is the speed
r is the radius of the circular path
At the beginning,
T = 50.4 N
v = 21.1 m/s
r = 2.51 m
So we can use the equation to find the mass of the rock:
Later, the radius of the string is decreased to
r' = 1.22 m
While the speed is increased to
v' = 51.6 m/s
Substituting these new data into the equation, we find the tension at which the string breaks:
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Answer:
The capacitance of the deflecting plates is .
Explanation:
The expression for the capacitance of the capacitor in terms of area and distance is as follows;
Here, C is the capacitance, A is the area, d is the distance and is the absolute permittivity.
Convert the side of the square from cm to m.
s= 3.0 cm
s= 0.030 m
Calculate the area of the square.
Put s= 0.030 m.
Convert distance from mm to m.
d= 5.0 mm
Calculate the capacitance of the deflecting plates.
Put ,
and
.
Therefore, the capacitance of the deflecting plates is .