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algol [13]
3 years ago
14

I will make you brainliest why magnets are used in motors

Physics
2 answers:
givi [52]3 years ago
6 0

Answer:

A motor uses magnet to create motion.

Explanation:

The attraction between a permanent magnet and an electromagnetic coil within a motor assembly is what causes a motor to rotate. When the source of electrical power is removed, the wire loses its magnetic qualities and the motor stops.

boyakko [2]3 years ago
5 0

Answer:

To produce magnetic field

Explanation:

When current passes through a coil in presence of magnetic field then torque is produced in it.This is the working principle of motor.

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If an object is to rest on an incline without slipping, then friction must equal the component of the weight of the object paral
leonid [27]

Answer:

\theta = tan^{-1}\mu

Explanation:

As we know that if the object is placed on the inclined plane then the force of friction on the object is counterbalanced by the component of the weight of the object along the inclined plane.

So we can say

F_f = mgsin\theta

now if we increase the inclination of the plane then the component of the weight weight along the inclined plane will increase and hence the friction force will also increase.

As we know that the limiting value or the maximum value of friction force at the static condition is given by

F_f = \mu N

N = mg cos\theta

so we have

F_f = \mu (mg cos\theta)

so we will have

mg sin\theta = \mu (mg cos\theta)

so now we have

tan\theta = \mu

so maximum possible angle of the inclined plane is

\theta = tan^{-1}\mu

3 0
3 years ago
A resistor is connected in series with an AC source that provides a sinusoidal voltage of v of t is equal to V times cosine of b
nekit [7.7K]
<h2>Answer:</h2>

In circuits, the average power is defined as the average of the instantaneous power  over one period. The instantaneous power can be found as:

p(t)=v(t)i(t)

So the average power is:

P=\frac{1}{T}\intop_{0}^{T}p(t)dt

But:

v(t)=v_{m}cos(\omega t) \\ \\ i(t)=i_{m}cos(\omega t)

So:

P=\frac{1}{T}\intop_{0}^{T}v_{m}cos(\omega t)i_{m}cos(\omega t)dt \\ \\ P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}cos^{2}(\omega t)dt \\ \\ But: cos^{2}(\omega t)=\frac{1+cos(2\omega t)}{2}

P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}(\frac{1+cos(2\omega t)}{2} )dt \\\\P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}[\frac{1}{2}+\frac{cos(2\omega t)}{2}]dt \\\\P=\frac{v_{m}i_{m}}{T}[\frac{1}{2}(t)\right|_0^T +\frac{sin(2\omega t)}{4\omega} \right|_0^T] \\ \\ P=\frac{v_{m}i_{m}}{2T}[(t)\right|_0^T +\frac{sin(2\omega t)}{2\omega} \right|_0^T] \\ \\ P=\frac{v_{m}i_{m}}{2}

In terms of RMS values:

V_{RMS}=V=\frac{v_{m}}{\sqrt{2}} \\ \\ I_{RMS}=I=\frac{i_{m}}{\sqrt{2}} \\ \\ Then: \\ \\ P=VI

7 0
3 years ago
A scientist at a space research center is doing research on near-Earth objects and determining the kinetic energy of a theoretic
Marysya12 [62]
<span>its kinetic energy is 7350kJ 
</span>

Kinetic energy is given as = \frac{1}{2} mv^{2}

Now, m = 12 gms = 0.012 kg
 And, velocity = 35 kilometers/second = 35000 m/sec

Kinetic energy is given as = \frac{1}{2} 0.012 kg * 35000*35000 m/[tex] s^{2}
                        = 6 10^{-2}×1225 ×10^{6} m/s^{2} 
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6 0
4 years ago
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Anna007 [38]

Answer:

You have to give us an answer choice : )

4 0
3 years ago
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If you have a pet that isn't getting nourishment from the food it eats, which organ might
tatuchka [14]
An organ I think that will have the problem is probably the kidney in an animal ! I tried my best
4 0
3 years ago
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