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adelina 88 [10]
3 years ago
6

How many fluorine atoms are present in 5.85 g of c2f4?

Chemistry
1 answer:
kozerog [31]3 years ago
4 0
The molar mass of C2F4 (tetrafluoroethylene) is equal to 100 g/mol. The number of moles of C2F4 in the given amount,
                               n = (5.85 g) / (100 g/mol) = 0.0585 mols C2F4
The number of molecules per mol is calculated through the equation,
                          (0.0585 mols) x (6.022 x 10^23)
Since there are 4 F atoms each molecule then, 
                           (0.0585 mols) x (6.022 x 10^23)(4)
                          = 1.41 x 10^23 atoms of F
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<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

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