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sammy [17]
3 years ago
15

calculate the (m/v) of nacl of a solution made by diluting 25.0 ml of a 7.50 (m/v)% NaCl solution to a total volume of 75.00 ml

Chemistry
2 answers:
postnew [5]3 years ago
8 0

Answer:

c

Explanation:

Elza [17]3 years ago
7 0

Answer:

2.5%

Explanation:

Given

M1 = 7.50%

M2 = ?

V1 = 25.0mL

V2 = 75.00mL

M1V1=M2V2

7.5x25=M2x75

M2=2.5%

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nordsb [41]

Answer:

2 grams.

Explanation:

H2 + O2 --->  H2O2

Using molar masses:

2*1 g hydrogen   reacts with 2*16  g oxygen.

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3 years ago
Through which conversion is energy released? adp to atp atp to adp nadp to nadph co2 and h2o to c6h12o6 and o2
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3 0
2 years ago
A 2.50 g sample of solid sodium hydroxide is added to 55.0 mL of 25 °C water in a foam cup (insulated from the environment) and
zlopas [31]

Answer:

37.1°C.

Explanation:

  • Firstly, we need to calculate the amount of heat (Q) released through this reaction:

<em>∵ ΔHsoln = Q/n</em>

no. of moles (n) of NaOH = mass/molar mass = (2.5 g)/(40 g/mol) = 0.0625 mol.

<em>The negative sign of ΔHsoln indicates that the reaction is exothermic.</em>

∴ Q = (n)(ΔHsoln) = (0.0625 mol)(44.51 kJ/mol) = 2.78 kJ.

  • We can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released to water (Q = 2781.87 J).

m is the mass of water (m = 55.0 g, suppose density of water = 1.0 g/mL).

c is the specific heat capacity of water (c = 4.18 J/g.°C).

ΔT is the difference in T (ΔT = final temperature - initial temperature = final temperature - 25°C).

∴ (2781.87 J) = (55.0 g)(4.18 J/g.°C)(final temperature - 25°C)

∴ (final temperature - 25°C) = (2781.87 J)/(55.0 g)(4.18 J/g.°C) = 12.1.

<em>∴ final temperature = 25°C + 12.1 = 37.1°C.</em>

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