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marin [14]
3 years ago
15

Suppose a disk with constant angular velocity has rotational kinetic energy 1280 J. If the moment of inertia of the disk is 35 k

g-m^2, then what is its angular velocity? (a) 7.604 rad/s (b) 8.552 rad/s (c) 10.12 rad/s (d) 6.818 rad/s (e) 9.952 rad/s (f) 8.935 rad/s f
Physics
1 answer:
lozanna [386]3 years ago
8 0

Answer:

Angular velocity of the disk is 8.552 rad/s

Explanation:

It is given that,

Rotational kinetic energy, KE = 1280 J

The moment of inertia of the disk, I = 35 kg m²

We have to find the angular velocity of the disk. In rotational mechanics the kinetic energy of the disk is given by :

KE=\dfrac{1}{2}I\omega^2

\omega=\sqrt{\dfrac{2KE}{I}}

\omega=\sqrt{\dfrac{2\times 1280\ J}{35\ kgm^2}}

\omega=8.552\ rad/s

Hence, the angular velocity of the disk is 8.552 rad/s.

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Two wheels having the same radius and mass rotate at the same angular velocity. One wheel is made with spokes so nearly all the
Mazyrski [523]

Answer:

C. The wheel with spokes has about twice the KE.

Explanation:

Given that

Mass , radius and the angular speed for both the wheels are same.

radius = r

Mass = m

Angular speed = ω

The angular kinetic energy KE given as

KE=\dfrac{1}{2}I\omega ^2

I=Moment of inertia for wheels

Wheel made of spokes

I₁ = m r²

Wheel like a disk

I₂ = 0.5 m r²

Now by comparing kinetic energy

\dfrac{KE_1}{KE_2}=\dfrac{I_1}{I_2}

\dfrac{KE_1}{KE_2}=\dfrac{mr^2}{0.5mr^2}

\dfrac{KE_1}{KE_2}=2

KE₁= 2 KE₂

Therefore answer is C.

5 0
3 years ago
True or False <br> Most magnets are made<br> from 100% aluminum
bazaltina [42]

Answer:

True

I hope it helps.

4 0
2 years ago
Read 2 more answers
Earth's surface receives about twice as much energy from the atmosphere than from the sun as a result of ____.
Oxana [17]
I think the answer is “greenhouse effect”
5 0
3 years ago
Water vapor enters a turbine operating at steady state at 500°C, 40 bar, with a velocity of 200 m/s, and expands adiabatically t
faltersainse [42]

Answer:

W = 5701 KW

Explanation:

From the question let inlet be labelled as point 1 and exit as point 2, for the fluid steam, we can get the following;

Inlet (1): P1 = 40 bar ; T1 = 500°C and V1 = 200 m/s

Exit(2) : At saturated vapour; P2 = 0.8 bar and V2 = 150 m/s

Volumetric flow rate = 15 m^(3)/s

Now, to solve this question, we assume constant average values, steeady flow and adiabatic flow.

Specific volume for steam at P2 = 0.8 bar in the saturated vapour state can be gotten from saturated steam tables(find a sample of the table attached to this answer).

So from the table,

v2 = 2.087 m^(3)/kg

Now, mass flow rate (m) = (AV) /v

Where AV is the volumetric flow rate.

Thus, the mass flow rate at exit could be calculated as;

m = 15/(2.087) = 7.17 kg/s

We also know energy equation could be defined as;

Q-W = m[(h1 - h2) + {(V2(^2) - (V1(^2)} /2)} + g(Z2 - Z1)]

Since the flow is adiabatic, potential energy can be taken to be zero. Therefore, we get;

-W = m[(h2 - h1) + {(V2(^2) - (V1(^2)} /2)}

From, table 2, i attached , at P1 = 40 bar and T1 = 500°C; specific enthalpy was calculated to be h1 = 3445.3 KJ/Kg

Likewise, at P2 = 0.8 bar; from the table, we get specific enthalpy as;

h2 = 2665.8 KJ/Kg

So we now calculate power developed;

W = - 7.17 [(2665.8 - 3445.3) + {(150^(2) - 200^(2))/2000 = 5701KW

Since the sign is not negative but positive, it means that the power is developed from the system.

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3 years ago
Scientists often work on projects for a long time and fail to see sources of error in their research. Which process allows an ou
Marina CMI [18]

Answer:

Peer Review

Explanation: I took the test

6 0
3 years ago
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