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Digiron [165]
3 years ago
7

Witch type of radio station can broadcast a signal the gratis distance

Physics
1 answer:
Nana76 [90]3 years ago
6 0
AM radio stations I believe
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Please fast answerrr thank you​
Vedmedyk [2.9K]

Answer:

50J

Explanation:

At the top you have(A)

KE_a = O

PE_a = 100J

KE + PE = 100J

At the bottom you have (C)

KE_c= 100J

PE_c=0J

KE+PE = 100J

At point C:

You are at half the height.

We know that at H, PE =100J

PE_c = mgH

At C,

PE_c= mg (H/2) *at half the height

*m and g stay the same

Intuitively, the higher you are, the more potential energy you have.

If you decrease the height by a half, your PE will also decrease

At A:

PE_a / (mg) = H

At B:

PE_b / (mg) = H/2

to also get H on the right hand side, multiply by 2

2 (PE_b/ (mg))= H

2PE_b / (mg) = H

Ok, now that we have set up 2 equations (where H is isolated), find PE at B

AT A = AT B *This way you are saying that H = H (you compare both equations)

PE_a / (mg) = 2x PE_b / (mg)

*mg are the same for both cancel them (you can do that because of the = sign)

PE_a =  2PE_b

We know that PE_a = 100J

100J/2 = PE_b

PE at b = 50J

**FIND KE at b

We know that

KE_b + PE_b is always 100J

100J = 50J + KE_b

KE_b = 50J

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2 years ago
Andre the Giant and Thumbelina are standing in the middle of an ice-skating rink facing each other. Andre the Giant pushes Thumb
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I don't know for sure but i think that it is because the force him pushing her pushed him back as well

Hope i helped

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3 years ago
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What does an element’s molar mass tell you about the element?
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Answer:

The molar mass of a compound tells you the mass of one mole of that substance. In other words, it tells you the number of grams per mole of a compound.

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Female scientist who came to america to study starts at harvard
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Is that a question? If it is not what its the question?
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How many different types of atoms are present in one molecule of aluminum hydroxide, Al(OH)3?
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There are approximately 3 different types of atoms that are present in one molecule of aluminum hydroxide, AI(OH)3.
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