<h2><u>Question</u><u>:</u><u>-</u></h2>
Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?
<h2><u>Answer:</u><u>-</u></h2>
<h3>Given,</h3>
=> Force applied by Ryan = 10N
=> Distance covered by the book after applying force = 30 cm
<h3>And,</h3>
30 cm = 0.3 m (distance)
<h3>So,</h3>
=> Work done = Force × Distance
=> 10 × 0.3
=> 3 Joules

Answer:
See the explanation below.
Explanation:
The force is a vector therefore we can decompose the force into components x & y. as we need the horizontal component of the force, we must use the cosine function of the angle.
![F_{1x}=30.8*cos(20)\\F_{1x}=28.94[N]\\F_{2x}=34.3*cos(20)\\\\F_{2x}= 32.23[N]](https://tex.z-dn.net/?f=F_%7B1x%7D%3D30.8%2Acos%2820%29%5C%5CF_%7B1x%7D%3D28.94%5BN%5D%5C%5CF_%7B2x%7D%3D34.3%2Acos%2820%29%5C%5C%5C%5CF_%7B2x%7D%3D%2032.23%5BN%5D)
Answer:43.34 m
Explanation:
Given
acceleration(a)
Initial Velocity(u)=0 m/s
After 6 s fuel runs out
Velocity after 6 s
v=u+at

After this object will start moving under gravity
height reached in first 6 s


s=36 m
After fuel run out distance traveled in upward direction is

here v=0
u=12 m/s




Answer: C) Increase the amplitude of the wavelenghth to increase the intensity.
Explanation: