Answer:
d) 2, 4-Dimethylpentane
Explanation:
2, 4-Dimethylpentane is the c_7 compound that gives 3 signals in the broadband proton decoupled ¹³C spectrum.
This compound is classified as an alkane and it's chemical formula is [(CH3C)2CH]2CH2. It is a hydrocarbon that has no odor. When it is combined with other gas compounds it gives high octane fuel.
Mass of CO₂ = 33 g
<h3>Further explanation </h3>
Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion produced by CO and H and O
Reaction
CH₄ + 2O₂⇒CO₂ + 2H₂O
mol CH₄ :

mol O₂ :

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients

Because O₂ ratio smaller then O₂ becomes the limiting reactants
So mol CO₂ from limiting reactants
mol CO₂ :

mass CO₂ :

By increasing atomic number