No, its not possible. Let's go back to 4th grades' basic science. 
"Energy can not be created or destroyed." 
This applies to everything, even atoms! 
Have a great day! ❤
        
             
        
        
        
Yes the answer is correct the plant uses the energy to grow and fertilize other plants
        
                    
             
        
        
        
Step 1 : Write balanced chemical equation.
CaF₂ can be converted to F₂ in 2 steps. The reactions are mentioned below.
I] 
II] 
The final balanced equation for this reaction can be written as

Step 2: Find moles of CaF₂ Using balanced equation 
We have 1.12 mol F₂
The mole ratio of CaF₂ and F₂ is 1:1

Step 3 : Calculate molar mass of CaF2.
Molar mass of CaF₂ can be calculated by adding atomic masses of Ca and F 
Molar mass of CaF₂ = Ca + 2 (F)
Molar mass of CaF₂ = 40.08 + 18.998 = 78.08 g
Step 4 : Find grams of CaF₂
Grams of CaF₂ = 
Grams of CaF₂ = 87.45 g 
87.45 grams of CaF2 would be needed to produce 1.12 moles of F2. 
 
        
                    
             
        
        
        
Answer:
if you look at the number at the top of the element square you can find the amount of positive atoms wich is also the amount of negative atoms. so if you count the valence electrons then that would be you difference
explanation:
Valence electrons are the amount of negative atoms on the outermost shell.
 
        
             
        
        
        
Answer:
The radius of tantalum (Ta) atom is 
Explanation:
From the Body-centered cubic (BBC) crystal structure we know that a unit cell length <em>a </em>and atomic radius <em>R </em>are related through

So the volume of the unit cell  is
 is 

We can compute the theoretical density ρ through the following relationship

where
n = number of atoms associated with each unit cell
A = atomic weight
 = volume of the unit cell
 = volume of the unit cell
 =  Avogadro’s number (
 =  Avogadro’s number ( atoms/mol)
 atoms/mol)
From the information given:
A = 180.9 g/mol
ρ = 16.6 g/cm^3
Since the crystal structure is BCC, n, the number of atoms per unit cell, is 2.
We can use the theoretical density ρ to find the radio <em>R</em> as follows:

Solving for <em>R</em>
![\rho=\frac{nA}{(\frac{64\sqrt{3}R^3}{9})N_{a}}\\\frac{64\sqrt{3}R^3}{9}=\frac{nA}{\rho N_{a}}\\R^3=\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}} \\R=\sqrt[3]{\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}](https://tex.z-dn.net/?f=%5Crho%3D%5Cfrac%7BnA%7D%7B%28%5Cfrac%7B64%5Csqrt%7B3%7DR%5E3%7D%7B9%7D%29N_%7Ba%7D%7D%5C%5C%5Cfrac%7B64%5Csqrt%7B3%7DR%5E3%7D%7B9%7D%3D%5Cfrac%7BnA%7D%7B%5Crho%20N_%7Ba%7D%7D%5C%5CR%5E3%3D%5Cfrac%7BnA%7D%7B%5Crho%20N_%7Ba%7D%7D%5Ccdot%20%5Cfrac%7B1%7D%7B%5Cfrac%7B64%5Csqrt%7B3%7D%7D%7B9%7D%7D%20%5C%5CR%3D%5Csqrt%5B3%5D%7B%5Cfrac%7BnA%7D%7B%5Crho%20N_%7Ba%7D%7D%5Ccdot%20%5Cfrac%7B1%7D%7B%5Cfrac%7B64%5Csqrt%7B3%7D%7D%7B9%7D%7D%7D)
Substitution for the various parameters into above equation yields
![R=\sqrt[3]{\frac{2\cdot 180.9}{16.6\cdot 6.023 \times 10^{23}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}\\R = 1.43 \times 10^{-8} \:cm = 0.143 \:nm](https://tex.z-dn.net/?f=R%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B2%5Ccdot%20180.9%7D%7B16.6%5Ccdot%206.023%20%5Ctimes%2010%5E%7B23%7D%7D%5Ccdot%20%5Cfrac%7B1%7D%7B%5Cfrac%7B64%5Csqrt%7B3%7D%7D%7B9%7D%7D%7D%5C%5CR%20%3D%201.43%20%5Ctimes%2010%5E%7B-8%7D%20%5C%3Acm%20%3D%200.143%20%5C%3Anm)