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denpristay [2]
3 years ago
12

What type of relationship occurs when one variable decreases while the other variable increases? a non-linear relationship a dir

ect relationship a positive relationship an inverse relationship
Physics
2 answers:
Arturiano [62]3 years ago
6 0

Answer:

inverse relationship

Explanation:

If one variable decreases and the other increases, it means there is an inverse relationship between the variables.

for example, in ideal gas equation,

PV = nRT

Where, P is the pressure, V is the volume, R be the gas constant and T be the absolute temperature.

If the temperature is constant, P V = constant

It means that the pressure is inversely  proportional to the volume of the gas.

liq [111]3 years ago
3 0
It is an inverse relationship because in this when you decrease a variable the other one increases.
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Which equations could be used as is, or rearranged to calculate for frequency of a wave? Check all that apply.
amm1812
-- Equations  #2  and  #6  are both the same equation,
and are both correct.

-- If you divide each side by  'wavelength', you get Equation #4,
which is also correct.

-- If you divide each side by  'frequency', you get Equation #3,
which is also correct. 
With some work, you can rearrange this one and use it to calculate
frequency.

Summary:

-- Equations #2, #3, #4, and #6 are all correct statements,
and can be used to find frequency.

-- Equations #1 and #5 are incorrect statements.
7 0
3 years ago
Read 2 more answers
If the distance of a charged particle from a wire changes from 10cm to 20 cm , what happens to its magnetic field
postnew [5]

Answer:

i would say it decreases

Explanation:

bc as distance grows the fields decrease

IM NOT SURE tho

5 0
3 years ago
Read 2 more answers
1.
Gwar [14]

<u>Answer:</u>

For 1: The correct option is Option C.

For 3: The final velocity of the opponent is 1m/s

<u>Explanation: </u>

During collision, the energy and momentum remains conserved. The equation for the conservation of momentum follows:

m_1u_1+m_2u_2=m_1v_1+m_2v_2      ...(1)

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of first object

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of second object

<u>For 1:</u>

We are Given:

m_1=150g=0.15kg\\u_1=?m/s\\v_1=0.85m/s\\m_2=3500g=3.5kg\\u_2=0m/s\\v_2=0.85m/s

Putting values in equation 1, we get:

(0.15\times u_1)+(3.5\times 0)=(3.5+0.15)\times 0.85\\\\u_1=20.683\approx 21m/s

Hence, the correct answer is Option C.

  • <u>For 2: </u>

Impulse is defined as the product of force applied on an object and time taken by the object.

Mathematically,

J=F\times t

where,

F = force applied on the object

t = time taken

J = impulse on that object

Impulse depends only on the force and time taken by the object and not dependent on the surface which is stopping the object.

Hence, the impulse remains the same.

  • <u>For 3:</u>

Let the speed in right direction be positive and left direction be negative.

We are Given:

m_1=240kg\\u_1=0m/s\\v_1=-1m/s\\m_2=80kg\\u_2=-2m/s\\v_2=?m/s

Putting values in equation 1, we get:

(240\times 0)+(80\times (-2))=(240\times (-1))+(80\times v_2)\\\\v_2=1m/s

Hence, the final velocity of the opponent is 1m/s and has moved backwards to its direction of the initial velocity.

4 0
3 years ago
A women who normally weighs 400 N stands on top of a ladder so high she is one full additional earth radius above the surface of
AveGali [126]

The woman weighs 100N now.

Explanation:

Given:

F is given as 400N

one full additional earth radius formed

To Find:

Weight of the woman=?

Solution:

We know that gravitational force is inversely proportional to the square of radius.

f_g=\frac{1}{r^2}

where

f_g is the gravitational force

r^2 is the radius square

So when radius is doubled, the force becomes one fourth of the original.

Therefore \frac{1}{4} \times400 = 100N

3 0
3 years ago
Plzz answer this question correctly
Leno4ka [110]

Answer:

by reducing friction.....

6 0
3 years ago
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