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Paul [167]
3 years ago
10

In describing a vector, what must you describe besides the magnitude?

Physics
1 answer:
Anton [14]3 years ago
7 0

Answer:

Direction

Explanation:

A vector is a geometrical representation of physical quantity. It has a particular direction with a specific magnitude.

In the geometry of space whether it is two dimensional or three dimensional the vector quantity has a specific direction. Such as a stone is thrown with a velocity in a particular direction.

The path of the stone in three-dimension shows its direction and speed is its magnitude.  

Hence, the velocity of stone has two property magnitude mentioned as speed and particular direction.

On writing the mathematical expressions for vectors, it is denoted by arrow mark on its top as shown below.

                          \vec{A}

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Answer:

Equation : Density = mass / volume

= 2.6 / 7.13

= 0.3646563815

Explanation:

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3 years ago
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a motorcycle stunt driver rides his motorcycle off a small ledge that is 8.4m high his initial velocity as he rides off the ledg
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1.3s

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An electromagnetic wave with an electric field that oscillates with a period of 8.43 ps is travelling in a vacuum. What is the w
marysya [2.9K]

"ps" stands for "pico-second".  It means 10⁻¹² second.

The period of this wave is 8.43 x 10⁻¹² second.

In a vacuum, the speed of any electromagnetic wave is 3 x 10⁸ m/s.

Wavelength = (speed) / (frequency)

But Frequency = 1 / period

So Wavelength = (speed) x (period)

Wavelength = (3 x 10⁸ m/s) x (8.43 x 10⁻¹² sec)

Wavelength = 2.5 x 10⁻³ meter

<em>Wavelength = 2.5 millimeters</em>

<em></em>

5 0
4 years ago
An ideal transformer has 60 turns on its primary coil and 300 turns on its secondary coil. If 120 V at 2.0 A is applied to the p
Taya2010 [7]

Explanation:

It is given that,

Number of turns in primary coil, N_p=60

Number of turns in secondary coil, N_s=300

Voltage in primary coil, V_p=120\ V

Current in primary coil, I_p=2\ A

We have to find the voltage and current in the secondary coli. Firstly calculating the voltage in secondary coil as :

\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}

\dfrac{60}{300}=\dfrac{120}{V_s}

V_s=720\ Volts

Now, calculating the current present in the secondary coil as :

\dfrac{N_p}{N_s}=\dfrac{I_s}{I_p}

\dfrac{60}{300}=\dfrac{I_s}{2\ A}

I_s=0.4\ A

<em>Hence, this is the required solution.</em>

3 0
3 years ago
What is the magnitude (in N/C) and direction of an electric field that exerts a 4.00 x 10^−5 N upward force on a −2.00 µC charge
emmasim [6.3K]

Answer:

The magnitude of electric field is 1.25\times10^{14}\ N/C in downward.

Explanation:

Given that,

Force F= 4.00\times10^{-5}\ N

Charge q= -2.00 μC

We know that,

Charge is negative, then the electric field in the opposite direction of the exerted force.

We need to calculate the magnitude of electric field

Using formula of electric force

F = qE

E = \dfrac{F}{q}

E=\dfrac{4.00\times10^{-5}}{-2.00\times1.6\times10^{-19}}

E=-1.25\times10^{14}\ N/C

Negative sign shows the opposite direction of electric force.

Hence, The magnitude of electric field is 1.25\times10^{14}\ N/C in downward.

8 0
4 years ago
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