Question

Reviewing Imaginary Numbers. Simplify I^12

Answer 1

Answer:

1

Step-by-step explanation:

$i^{12}= i^{2} *i^{2} *i^{2} *i^{2} *i^{2} *i^{2}$

Remember that $i^{2}=-1$

Plug it in:

$i^{12}= (-1)^{2} *(-1)^{2} *(-1)^{2} *(-1)^{2} *(-1)^{2} *(-1)^{2}$

$=1*1*1*1*1*1$

$=1$