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3 years ago

Reviewing Imaginary Numbers. Simplify I^12

Mathematics

1 answer:

melamori03 [73]3 years ago

6 0

Answer:

Step-by-step explanation:

$i^{12}= i^{2} *i^{2} *i^{2} *i^{2} *i^{2} *i^{2}$

Remember that $i^{2}=-1$

Plug it in:

$i^{12}= (-1)^{2} *(-1)^{2} *(-1)^{2} *(-1)^{2} *(-1)^{2} *(-1)^{2}$

$=1*1*1*1*1*1$

$=1$

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