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2 years ago

An ideal gas is sealed in a container at constant volume. if the temperature t is increased to 4t, the pressure will be:

Physics

2 answers:

Westkost [7]2 years ago

6 0

I believe that it would increase to 4p

valentina_108 [34]2 years ago

6 0

The pressure is proportional to the ABSOLUTE temperature. If the ABSOLUTE temperature increases by a factor of 4, the pressure will too ... to 4p. The ABSOLUTE temperature is the number of degrees above Absolute Zero. So for example, if the gas started out at, say 100 CELSIUS, you'd have to heat it to 1219 Celsius, because Zero Celsius is 273 Kelvin (absolute).

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3 years ago

Explain the difference between speed and velocity and indicate if these are scalar or vector quantities

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2 years ago

A wheel has a radius of r = 2.0 m and it rolls down a smooth incline. The height of the incline is h = 8.0 m . What is the angul

zepelin [54]

The angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

The angular velocity (ω) of an object is the rate at which the object's angle position is changing in relation to time.

For a wheel attached to an incline angle, the angular velocity can be computed by considering the conservation of energy theorem.

As such the total kinetic energy (K.E) and rotational kinetic energy (R.K.E) at a point is equal to the total potential energy (P.E) at the other point.

i.e.

P.E = K.E + R.K.E

$\mathbf{mgh = \dfrac{1}{2}m(r \times \omega)^2 + \dfrac{1}{2}\times I \times \omega^2}$

$\mathbf{gh = \dfrac{1}{2}(r \times \omega)^2 + \dfrac{1}{2}\times r^2 \times \omega^2}$

$\mathbf{2 \times \dfrac{gh}{r^2} =\omega^2 + \omega^2}$

$\mathbf{2 \omega^2=2 \times \dfrac{9.81 \times 8 m }{2.0 ^2} }$

$\mathbf{\omega^2=\dfrac{39.24 }{2}}$

$\mathbf{\omega=\sqrt{19.62 } \ rad/sec}$

$\mathbf{\omega=4.429 \ rad/sec}$

Therefore, we can conclude that the angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

Learn more about angular velocity here:

brainly.com/question/1452612

4 0

2 years ago

Read 2 more answers

Circular Motion A 650-kg car moving at 8.5 m/s takes a turn around a circle with a radius of 48.0 m. Determine the acceleration

ollegr [7]

Answer:

Explanation:

The mass of the car doesn't matter because On a flat curve the mass of the car does not affect the speed at which it can stay on the curve. You would need the mass if you were solving the the centripetal force acting on the car, but not the acceleration.

$a=\frac{v^2}{r}$ and filling in

$a=\frac{(8.5)^2}{48.0}$ and we need 2 significant digits in our answer. That means that

a = 1.5 m/sec²

8 0

2 years ago