Answer:
Part a)

Part b)

Part C)


Part d)
In horizontal direction velocity will remain constant

in vertical direction we have

Explanation:
Part a)
Horizontal speed of the cannon

angle of projection

now we have
horizontal speed = 
vertical speed = 
now the time taken by it to cover the distance 100 m from the wall



Part b)
Since it hits the ground in the same time
so the height of the castle is given as



Part C)
At highest point of the projection
the vertical component of the velocity will become zero
so we will have


Part d)
In horizontal direction velocity will remain constant
so we have

in vertical direction we have



Part e)
Your answer is B. The human eye can only detect color and Tv waves
Answer:
–8.35 m/s²
Explanation:
We'll begin by converting 104 km/h to m/s. This can be obtained as follow:
3.6 Km/h = 1 m/s
Therefore,
104 km/h = 104 km/h × 1 m/s / 3.6 Km/h
104 km/h = 28.89 m/s
Thus, 104 km/h is equivalent to 28.89 m/s.
Finally, we shall determine the deceleration of the car. This can be obtained as follow:
Initial velocity (u) = 28.89 m/s
Final velocity (v) = 0 m/s
Distance (s) = 50 m
Deceleration (a) =?
v² = u² + 2as
0² = 28.89² + (2 × a × 50)
0 = 834.6321 + 100a
Collect like terms
0 – 834.6321 = 100a
–834.6321 = 100a
Divide both side by 100
a = –834.6321 / 100
a = –8.35 m/s²
Thus, the deceleration of the car is –8.35 m/s².
Answer:
35 m/s^2
Explanation:
Decceleration = change in velocity / change in time
= ( 70 m/s ) / 2 seconds = 35 m/s^2
DEcceleration = 35 m/s^2
Jason's speed changes by - 35 m/s^2
Answer:
Yes, there is such a way.
Explanation:
If currents flow in the same direction in two or more long parallel wires, there will be an attractive force between the wires. If the current flows in different directions, there will be a repulsive force between the wires. In this case, these three parallel wires, can be be made to carry current in the same direction, creating an attractive force between all three wires.
Note that it is not possible to have at the least one of them carry current in the opposite direction and still have an attractive current between them.