By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.
<h3>What are the limits?</h3>
First, we need to find the limits.
We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.
So if 58 in is the 100%, the 26% and 43% of that are:
- 26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
- 43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.
But we know that the CG is found to be 45.5% MAC, then it measures:
(45.5%/100%)*58in = 0.455*58in = 26.39 in
We need to compare it with the largest limit, so we get:
26.39 in - 24.94 in = 1.45 in
This means that the CG is 1.45 inches out of limits.
If you want to learn more about percentages, you can read:
brainly.com/question/14345924
On a Fahrenheit thermometer, the gas becomes 18 degrees warmer.
The real world examples that I can give is the everyday
things that we do and some of these are:
I am walking to the end of the room holding three textbooks.
Playing tug of war with friends.
Getting the groceries from the car and put it inside of your house.
Answer:
Explanation:
The relation between time period of moon in the orbit around a planet can be given by the following relation .
T² = 4 π² R³ / GM
G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .
Substituting the values in the equation
(.3189 x 24 x 60 x 60 s)² = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)
759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )
M = .06424 x 10²⁵
= 6.4 x 10²³ kg .
The answer is; The sun will turn into a red giant
This occurs as the hydrogen fuel in the fusion core of the sun begins to deplete. When the hydrogen fuel is depleted, the star begins to collapse on itself due to gravity. This pressure causes the heavier helium to begin fusing in the area around the core. The stars begin to heat up again producing enough energy to push out the outer shells of the star. This causes the star to expand. The outer shells become less hot hence the decrease in luminosity of red giants.
