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DanielleElmas [232]
3 years ago
12

Hello!! I need help please! Please explain how I can identify a percipitate in a reaction! I need help with chemistry ha

Chemistry
1 answer:
antiseptic1488 [7]3 years ago
5 0
Generally speaking a precipitate is something that will form as a result of the reaction.  It generally is a solid material.

Sodium and nitrates are soluble so Calcium Phosphate would precipitate out....


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A 6.1-kg solid sphere, made of metal whose density is 2600 kg/m3, is suspended by a cord. When the sphere is immersed in a liqui
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Answer:

Density of the liquid = 1470.43 kg/m³

Explanation:

Given:

Mass of solid sphere(m) = 6.1 kg

Density of the metal = 2600 kg/m³

Thus volume of the liquid :

Volume(V)=\frac{Mass(m)}{Density (\rho)}

Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³

The volume of water displaced is equal to the volume of sphere (Archimedes' principle)

Volume displaced = 0.002346 m³

Buoyant force =\rho\times gV

Where

\rho is the density of the fluid

g is the acceleration due to gravity

V is the volume displaced

The free body diagram of the sphere is shown in image.

According to image:

mg=\rho\times gV+T

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Applying in the equation to find the density of the liquid as:

6.1\times 9.81=\rho\times 9.81\times 0.002346+26

33.841=\rho\times 9.81\times 0.002346

\rho=\frac{33.841}{9.81\times 0.002346}

\rho=1470.43 kgm^3

<u>Thus, the density of the liquid = 1470.43 kg/m³</u>

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What makes up a Solar System?
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Zn(CrO4)2<br> What is the name of the compound
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Explanation:

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What is the basic principle of chromatography process ​
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A military jet cruising at an altitude of 12.0km and speed of 1300./kmh burns fuel at the rate of 46.2/Lmin. How would you calcu
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Answer:

2,452.12 L of fuel the jet consumes on a 1150 km mission.

Explanation:

Speed of the jet = 1300 km/h

1 hour = 60 minutes

1300 km/h=\frac{1300 km}{60 min}=21.667 km/min

Rate at which jet consumes fuel = 46.2 L/min

Distance covered by jet by consuming 1 liter fuel or mileage = R

R = \frac{21.667 km/min}{46.2 L/min}=0.4690 km/L

The amount of fuel the jet consumes on a 1150 km mission will = V

Amount of fuel = \frac{Distance}{Mileage}

V=\frac{1150 km}{0.4690 km/L}=2,452.12 L

2,452.12 L of fuel the jet consumes on a 1150 km mission.

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