Answer:
Explanation:
We are asked to convert from molecules of water to moles.
<h3>1. Avogadro's Number </h3>
1 mole of any substance contains the same number of particles (atoms, molecules, formula units, etc). This is Avogadro's Number: 6.022*10²³. In this problem, the particles are molecules of water.
<h3>2. Convert Molecules to Moles</h3>
Use Avogadro's Number to make a ratio.
Multiply by the number of molecules given: 2.54 *10²⁹
Flip the ratio so the units of molecules of water cancel.
Condense the problem into 1 fraction.
2.54 *10²⁹ molecules of water are 421, 786.7818 moles of water.
Answer:
Explanation:
Take a look at the balanced chemical equation that describes this reaction
Cu
(
s
)
+
2
AgNO
3
(
a
q
)
→
Cu
(
NO
3
)
2
(
a
q
)
+
2
Ag
(
s
)
Notice that the chemical equation provides you with information about how many moles of each chemical species takes part in this reaction.
More specifically, you know that
1
mole of solid copper will react with
2
moles of silver nitrate to produce
1
mole of aqueous copper(II) nitrate and
2
moles of solid silver.
So, assuming that you have enough silver nitrate available to allow for all the sample of copper to react, you can expect the reaction to produce twice as many moles of solid silver than you have moles of solid copper taking part in the reaction.
Use the molar mass of copper to calculate how many moles you have in your sample
1.00
g
⋅
1 mole Cu
63.546
g
=
0.01574 moles Cu
According to the aforementioned mole ratio, the reaction will produce
0.01574
moles Cu
⋅
2
a
moles Ag
1
mole Cu
=
0.03148 moles Ag
Finally, use the molar mass of silver to convert the number of moles to grams
Answer:
0.529
Explanation:
Let's consider the reaction A → Products
Since the units of the rate constant are s⁻1, this is a first-order reaction with respect to A.
We can find the concentration of A at a certain time t (![[A]_{t}](https://tex.z-dn.net/?f=%5BA%5D_%7Bt%7D)
) using the following expression.
![[A]_{t}=[A]_{0}.e^{-k\times t}](https://tex.z-dn.net/?f=%5BA%5D_%7Bt%7D%3D%5BA%5D_%7B0%7D.e%5E%7B-k%5Ctimes%20t%7D)
where,
[A]₀: initial concentration of A
k: rate constant
![[A]_{t}=0.548M.e^{-3.6\times 10^{-4}s^{-1}\times 99.2s }](https://tex.z-dn.net/?f=%5BA%5D_%7Bt%7D%3D0.548M.e%5E%7B-3.6%5Ctimes%2010%5E%7B-4%7Ds%5E%7B-1%7D%5Ctimes%2099.2s%20%7D)
![[A]_{t}=0.529 M](https://tex.z-dn.net/?f=%5BA%5D_%7Bt%7D%3D0.529%20M)
The given question is incomplete. The complete question is:
A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.
Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
moles of 
(solute) = 
Now put all the given values in the formula of molality, we get
Therefore, the molarity of solution is 1.20 mol/L
Answer:
if i remember correctly i beleive its A 1.8 x 10^24
but im not for sure also i think you forgot the 24
Explanation:
