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3 years ago

Help this is really hars

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

6 0

We have to find the slope of the line that passes through this points:
p1(-2,15), p2(-8,-5)
the slope of a line through two points is calculated like this:
m = (y2 - y1)/(x2 - x1)
where x1,y1,x2,y2 are the coordinates of the two points, so we have:
m = (-5 - 15)/(-8 - (-2))
m = (-20)/(-8 + 2)
m = -20/-6
m = 10/3
that is the line slope

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A percent is a ratio of the ________ to the _______.

riadik2000 [5.3K]

Answer:

A percent is a ratio of the parts to the whole

Step-by-step explanation:

If you had 30/100, 30% as a percentage, 30 would be the parts and 100 would be the whole

7 0

2 years ago

A school baseball team raised $810 for new uniforms.Each player sold 1 book of tickets.There were 10 tickets in a book and each

Leviafan [203]

Answer:

The school baseball team sold 270 tickets

Step-by-step explanation:

Step 1

Identify the total amount of tickets sold by each player;

1 player=1 book of tickets

But 1 book=10 tickets

Step 2

Express the total cost of ticket sales per book as follows;

total cost=cost per ticket×number of tickets per book

where;

cost per ticket=$3

number of tickets per book=10

replacing;

total cost=(3×10)=$30

Step 3

Using the expression below, solve for the number of tickets sold

Total amount raised=price per ticket×number of tickets sold

where;

total amount raised=$810

price per ticket=$3

number of tickets sold=n

replacing;

810=3×n

3 n=810

n=810/3=270

n=270

The school baseball team sold 270 tickets

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%204x-15%3D3" id="TexFormula1" title="\sf 4x-15=3" alt="\sf 4x-15=3" align="absmiddle" cl

AnnZ [28]

Answer:

$4x - 15 = 3 \\ 4x = 3 + 15 \\ 4x = 18 \\ x = \frac{18}{4} \\ x = \frac{9}{2} \\ x = 4.5$

hope helpful <3

5 0

3 years ago

Read 2 more answers

The matrix A= (−3 0 1, 2 −4 2, −3 −2 1) has one real eigenvalue. Find this eigenvalue, its multiplicity, and the dimension of th

Aliun [14]

Answer:

a) -4

b) 1

c) 1

Step-by-step explanation:

a) The matrix A is given by:

$A=\left[\begin{array}{ccc}-3&0&1\\2&-4&2\\-3&-2&1\end{array}\right]$

to find the eigenvalues of the matrix you use the following:

$det(A-\lambda I)=0$

where lambda are the eigenvalues and I is the identity matrix. By replacing you obtain:

$A-\lambda I=\left[\begin{array}{ccc}-3-\lambda&0&1\\2&-4-\lambda&2\\-3&-2&1-\lambda\end{array}\right]$

and by taking the determinant:

$[(-3-\lambda)(-4-\lambda)(1-\lambda)+(0)(2)(-3)+(2)(-2)(1)]-[(1)(-4-\lambda)(-3)+(0)(2)(1-\lambda)+(2)(-2)(-3-\lambda)]=0\\\\-\lambda^3-6\lambda^2-12\lambda-16=0$