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3 years ago

The humidity levels inside the greenhouse.

Chemistry

1 answer:

kkurt [141]3 years ago

8 0

C since it depends on temperature changes.

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Please help asap How can the effects of technology be described? This is Science not Chemistry sry

Sindrei [870]

Answer:

Chemistry is used in forensic science to uncover information from physical evidence.

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3 years ago

Which food, Cheetos® or Goldfish, had more calories per gram?

Naddik [55]

Goldfish
170/28 > 130/28

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3 years ago

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A student sees a commercial that claims a new dishwasher is energy efficient. Compared to less efficient dishwashers, this means

zaharov [31]

It’s either a or b but I’m not sure

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2 years ago

The mass in g of 3 moles Al .

Damm [24]

Answer:

81 gm

Explanation:

The mass of 1 mole is 27 g

So, Mass of 3 moles of Aluminium would be 3 × 27 = 81 gm..Thus mass of 3 Moles of Aluminium is 81 gm.

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3 years ago

Hydrogen peroxide decomposes to water and oxygen at constant pressure by the following reaction: 2H2O2(l) → 2H2O(l) + O2(g) ΔH =

Mashcka [7]

<u>Answer:</u> The amount of heat released is -7.203 kJ

<u>Explanation:</u>

The given chemical equation follows:

$2H_2O_2(l)\rightarrow 2H_2O(l )+O_2(g);\Delta H=-196kJ$

To calculate the enthalpy change for 1 mole of the hydrogen peroxide, we use unitary method:

When 2 moles of hydrogen peroxide is reacted, the enthalpy of the reaction is -196 kJ

So, when 1 mole of hydrogen peroxide will react, the enthalpy of the reaction will be $\frac{-196}{2}\times 1=-98kJ$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of hydrogen peroxide = 2.50 g

Molar mass of hydrogen peroxide = 34 g/mol

Putting values in above equation, we get:

$\text{Moles of hydrogen peroxide}=\frac{2.50g}{34g/mol}=0.0735mol$

To calculate the heat of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

$q$ = amount of heat released

n = number of moles = 0.0735 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -98 kJ/mol

Putting values in above equation, we get:

$-98kJ/mol=\frac{q}{0.0735mol}\\\\q=(-98kJ/mol\times 0.0735mol)=-7.203kJ$

Hence, the amount of heat released is -7.203 kJ

8 0

3 years ago