I think the chemical reaction is:<span>
N2H4 + 2 H2O2-> N2 + 4H2O
We are given the amount reactants allowed to react. This will be the starting point of the reaction. First, is to find the limiting reactant.
9.24 g H2O2 ( 1 mol / 34.02 g ) = 0.27 mol H2O2
6.56 g N2H4 ( 1mol / 32.06) = 0.20 mol N2H4
Since from the reaction we have 1:2 ratio of the reactants then the limiting reactant is hydrogen peroxide. We will use this to find the amount of N2 produced.
0.27 mol H2O2 ( 1 mol N2 / 2 mol H2O2 ) ( 14.01 g N2 / 1 mol N2) =1.89 g N2
</span>
- The density of the mineral fragment is
(20.47 g/cm3).
- Density can be regarded as<em> ratio of mass to the volume </em>of the object.
Density = (mass/ volume)
Given:
volume of mineral fragments= 2.57 cm3
mass = 52.6 g
density of the mineral fragment = (52.6/2.57)
= 20.47 g/cm3
- Therefore, density of the mineral fragment is (20.47 g/cm3)
Learn more at: brainly.com/question/13594966
Answer:
The number of atoms contained by one molecule of Iron (II) Sulfate are 6.
Explanation:
Iron (II) Sulfate is mage up of two parts. One is the Positive part which constitutes of Fe⁺² and a negative part which constitutes of a polyatomic anion i.e. SO₄²⁻. As there are four Oxygen and one sulfur atom in sulfate Ion so sulfate ion contains 5 atoms in total. Therefore, five atoms from sulfate iona dn one atom of Iron ion makes a total of 6 atoms in one molecule of Iron (II) Sulfate.
The balanced chemical equation is:
2Fe+3H2O=Fe2O3+3H2
We are given the amount of water to be used in the reaction. This will be the starting point for the calculations.
3 mol H2O ( 1 mol Fe2O3 / 3 mol H2O ) = 1 mol Fe2O3
Therefore, the correct answer is option B.
Answer:
The answer to your question is in the attachment.
Explanation:
Tell me if you understand