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3 years ago

We have f '(x) = 6x2 + 6x − 432, so f ''(x) = 12x+6 correct: your answer is correct. , which equals 0 when

1 answer:

3 0

The derivative of the first derivative given to be, f'(x) = 6x² + 6x - 432 is given to be,
f''(x) = 12x + 6

As asked in the given, the value of the second derivative becomes zero when the value of x is,
f"(x) = 0 = 12x + 6

12x + 6 = 0

Subtract 6 from both sides of the equation such that,
12x = -6

Divide both sides of the equation by 12 giving us an answer of
x = -1/2.

Hence, x = -1/2.

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Is (4,2) a solution of the system y=x-2 and y=3x+4

babunello [35]

Answer:

False

Step-by-step explanation:

y=x-2 y=3x+4

Substitute the point into both equations and see if it is true

2=4-2

2=2 true

and

2=3*4+4

2 = 12+4

2 =16

False

It is not a solution

4 0

3 years ago

Read 2 more answers

1/4k = 3 (-1/4k + 3)

Arada [10]

Answer:

For the expression $\frac{1}{4} k = 3 (-\frac{1}{4}k +3)$

k = 9 is the required solution.

Step-by-step explanation:

Here, the given expression is $\frac{1}{4} k = 3 (-\frac{1}{4}k +3)$

Solving the above expression for k, we get:

$\frac{1}{4} k = 3 (-\frac{1}{4}k +3) \implies \frac{k}{4} = (\frac{-3}{4}k) + 9$

or, $\frac{k}{4} + (\frac{3}{4}k) = 9 \implies \frac{k + 3k}{4} = 9$

or, $\frac{4k}{4} = 9 \implies k =9$

or, k = 9

Hence for the expression $\frac{1}{4} k = 3 (-\frac{1}{4}k +3)$

k = 9 is the required solution.

8 0

3 years ago

Sally needs 6 gallons of water, but she only has a 2 quart pitcher. How many times does she need to fill it up to make 6 gallons

Lilit [14]

Answer: E

Step-by-step explanation: 1 gallon is equal to 4 quarts. If Sally needs to fill and refill a 2 quart pitcher with 6 gallons of water, multiply 6 by 4 to get 24.

6 0

4 years ago

I need help on this asap

yaroslaw [1]

The answer is y=3/5x-2

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3 years ago

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A circular clock face has a radius of 3.5 inches. What is the area of the clock face? Round to the nearest tenth. Use 3.14 for p

gtnhenbr [62]

The area is about 316 in2
Step-by-step Divide 63 by π and by 2 to determine the radius of the clock. 63÷2÷π≈10. To find the area of the face of the clock multiply π by 102

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3 years ago