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sladkih [1.3K]
3 years ago
14

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: CaO (s) H 2O (l) Ca(OH) 2 (s) In a parti

cular experiment, a 2.00-g sample of CaO is reacted with excess water and 2.14 g of Ca(OH) 2 is recovered. What is the percent yield in this experiment
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
8 0
Find the moles of CaO

divide mass (2.0g) by the RFM which is 56 (Ca is 40 add that to O which is 16 making 56) this gives 0.0356 moles.

Find the theoretical mass by multiplying the moles of CaO (which is 0.0356 as there are no balancing number making the ratio 1:1) by the RFM of Ca(OH)2 which is 74 (40+16+16+1+1)

74 (Ca(OH)2 RFM) x 0.0357 (CaO moles) = 2.6g which is the theoretical mass of Ca(OH)2

Find percentage yield by dividing the actual mass of Ca(OH)2 by the theoretical and then x100 this Should give you 82.3%
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Si 100 monedas tienen una masa total de 226.13g. Cual es la masa de una moneda
galben [10]

The mass of a coin : 2.2613 g

<h3>Further explanation  </h3>

Algebraic expressions in mathematics are a combination of coefficients, numbers, variables, constants and arithmetic operations such as addition, subtraction, multiplication, and division.  

The main composition of algebraic expressions are:  

  • 1. phrases  

algebraic forms separated by arithmetic operations  

consists of one phrase (monomial) to many phrases (polynomial)  

  • 2. variables  

is a value that can be changed, can be in the form of letters, for example, x, y, a, b, etc.  

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<em>If 100 coins have a total mass of 226.13g. What is the mass of a coin</em>

We can make this statement in the form of an algebraic equation :

100 coins=226.13 g

then the mass of a coin :

\tt \dfrac{1}{100}\times 226.13~g=2.2613~g

5 0
2 years ago
Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

  1. C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
  3. 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

7 0
3 years ago
Select all the correct locations.
NikAS [45]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

The land breeze arrow is correct

The rest are incorrect.

Warm air should 'rise' by the land

This air then moves towards the sea and cools down

The cool air would then sink

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

5 0
3 years ago
Read 2 more answers
30. The density of an unknown gas at 27°C and 2 atm pressure is equal with density of N2 gas at
Zanzabum

Answer:

Molar mass of the unknown gas is 64.6 g/mol

Explanation:

Let's think this excersise with the Ideal Gases Law.

We start from the N₂. At STP conditions we know that 1 mol of anything occupies 22.4L.

We apply: P . V = n . R . T

5 atm . V = 1 mol . 0.082 . 325K

V = (1 mol . 0.082 . 325K) / 5 atm = 5.33 L

It is reasonable to say that, if we have more pressure, we may have less volume.

As this is the volume for 1 mol of N₂, our mass is 28 g. Then, the density of the nitrogen and the unknown gas is 28 g/5.33L = 5.25 g/L

Our unknown gas has, this density at 27°C and 2 atm.

If we star from this, again: 1 mol of any gas occupy 22.4L at STP, we can calculate the volume for 1 mol at those conditions:

P₁ . V₁ / T₁ = P₂ . V₂ / T₂

1 atm . 22,4L / 273K = 2 atm . V₂ / 300K

Remember that the value for T° is Absolute (T°C + 273)

[ (1 atm . 22.4L / 273K) . 300K] / 2 atm = V₂ → 12.3L

This is the volume for 1 mol of the unknown gas at 2 atm and 27°C

We use density to determine the mass: 12.3 L . 5.25 g/L = 64.6 g

That's the molar mass: 64.6 g/mol

6 0
2 years ago
What is the total mass of the reactants in the equation below?
Keith_Richards [23]

Answer:

266.7 g

Explanation:

Molar mass of AlCl3=133.3405 g

2AlCl3=2×133.34

          =266.7 g

Please mark brainliest

4 0
2 years ago
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