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Lilit [14]
3 years ago
6

In a particular enzyme, an alanine residue is located in a cleft where the substrate binds. A mutation that changes this residue

to a glycine has little effect on activity; however, another mutation, which changes the alanine to a glutamate residue, leads to a complete loss of activity. Provide a brief explanation for these observations.
Chemistry
1 answer:
TiliK225 [7]3 years ago
5 0

Explanation:

There are non-polar side chains also present in alanine. And, these non-polar side chains are involved in some hydrophobic interactions in active sideand then it changes into polar amino acid glutamate that will destroy the hydrophobic interaction.

Whereas in glycine there is only hydrogen present in the side chain therefore, it will not affect much.

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You are balancing an ionic compound. Let's call it: AB.
rewona [7]

Answer:- A_3B_2

Explanations:- It is given that the charge for A is +2 and the charge for B is -3. The over all compound is neutral means the over all charge is zero. For making the over all charge zero, we need 3 positive ions and 2 negative ions. This makes a +6 charge for A and -6 charge for B and the over all charge is zero.

Also, if we think about the criss cross then charge of A becomes the subscript of B and the charge of B becomes the subscript of A.

So, the formula of the ionic compound is A_3B_2 . In this compound the ratio of A to B is 3:2.

The balanced equation could be shown as:

3A+2B\rightarrow A_3B_2



8 0
3 years ago
What is the use of a pedigree chart? Please do not answer wat a perigee chart is!.
FinnZ [79.3K]
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8 0
4 years ago
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Which of the following has the most energy?
iren2701 [21]
Ultraviolet rays has the most energy
8 0
3 years ago
During the formation of an ionic compound, the element with the higher ionization energy will gain electrons.
Lesechka [4]
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8 0
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Lab 27. stoichiometry and chemical reactions: which balanced chemical equation best represents the thermal decomposition of sodi
Cloud [144]
Answer:
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<span>                       2 NaHCO</span>₂<span> </span> →<span>  Na</span>₂<span>CO</span>₃<span> (s)  </span>+ <span> CO</span>₂<span> (g)  +  H</span>₂<span>O (g)
</span>
Explanation:
                   Let suppose you burn 168 g ( 2 moles ) of NaHCO₃, a gas will produced and product is left behind. On measuring the product formed it will be almost equal to 105 g. This shows that the product is Na₂CO₃ and 1 mole of it is being produced after decomposition of sodium bicarbonate.
5 0
3 years ago
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