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Lilit [14]
3 years ago
6

In a particular enzyme, an alanine residue is located in a cleft where the substrate binds. A mutation that changes this residue

to a glycine has little effect on activity; however, another mutation, which changes the alanine to a glutamate residue, leads to a complete loss of activity. Provide a brief explanation for these observations.
Chemistry
1 answer:
TiliK225 [7]3 years ago
5 0

Explanation:

There are non-polar side chains also present in alanine. And, these non-polar side chains are involved in some hydrophobic interactions in active sideand then it changes into polar amino acid glutamate that will destroy the hydrophobic interaction.

Whereas in glycine there is only hydrogen present in the side chain therefore, it will not affect much.

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How do the forces change when a friend helps you push a door
inysia [295]

The net force applied will increase.

8 0
3 years ago
What is the mass of 0.31 1 mol of the element<br> potassium (K)?<br> Answer in units of g
snow_lady [41]

Answer:

0.31 mol K x 39.1 grams K/ 1 mol k = 12.1 g

Explanation:

molar mass of K: 39.1

In order to find the mass in 0.31 mol of K, you must covert moles to grams. In one mole of Potassium there is 39.1 grams.

8 0
3 years ago
it takes 60 days for 1024 grams of element XY to decay to 32 grams. what is the half life of element XY
KonstantinChe [14]

Answer:

The half life of element XY is 12 days

Explanation:

Given:

Time taken for  1024 grams to decay into 32 grams  = 60 days

To Find:

The half life of element XY = ?

Solution:

The Half life is calculated by

N = N_0 (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}

t_{\frac{1}{2}} =\frac{t}{log_{\frac{1}{2}}( \frac{N(t)}{N_0})}}

Substituting the values,

t_{\frac{1}{2}} =\frac{60}{log_{\frac{1}{2}}( \frac{32}{1024})}}

t_{\frac{1}{2}} =\frac{60}{log_{\frac{1}{2}}(0.03125)}}

t_{\frac{1}{2}} =\frac{60}{5}

t_{\frac{1}{2}} = 12

5 0
3 years ago
6.023*10^26 molecules of hydrogen gas into mass in gram<br>​
balandron [24]

Answer:

Avogadro’s Number

Avogadro’s NumberIt certainly is easy to count bananas or to count elephants (as long as you stay out of their way). However, you would be counting grains of sugar from your sugar canister for a long, long time. Atoms and molecules are extremely small – far, far smaller than grains of sugar. Counting atoms or molecules is not only unwise, it is absolutely impossible. One drop of water contains about 10 22 molecules of water. If you counted 10 molecules every second for 50 years without stopping you would have counted only 1.6 × 10 10 molecules. Put another way, at that counting rate, it would take you over 30 trillion years to count the water molecules in one tiny drop.

Avogadro’s NumberIt certainly is easy to count bananas or to count elephants (as long as you stay out of their way). However, you would be counting grains of sugar from your sugar canister for a long, long time. Atoms and molecules are extremely small – far, far smaller than grains of sugar. Counting atoms or molecules is not only unwise, it is absolutely impossible. One drop of water contains about 10 22 molecules of water. If you counted 10 molecules every second for 50 years without stopping you would have counted only 1.6 × 10 10 molecules. Put another way, at that counting rate, it would take you over 30 trillion years to count the water molecules in one tiny drop.Chemists needed a name that can stand for a very large number of items. Amedeo Avogadro (1776 – 1856), an Italian scientist, provided just such a number. He is responsible for the counting unit of measure called the mole. A mole (mol) is the amount of a substance that contains 6.02 × 10 23 representative particles of that substance. The mole is the SI unit for amount of a substance. Just like the dozen and the gross, it is a name that stands for a number. There are therefore 6.02 × 10 23 water molecules in a mole of water molecules. There also would be 6.02 × 10 23 bananas in a mole of bananas, if such a huge number of bananas ever existed

3 0
3 years ago
Read 2 more answers
Because of this, railroads use the reaction to provide molten steel to weld steel rails together when laying track. When 23.00g
k0ka [10]

Answer:

0.288 mole of Fe.

Explanation:

We'll begin by calculating the number of mole present in 23.00g of iron(III) oxide (Fe2O3). This can be obtained as follow:

Mass of Fe2O3 = 23 g

Molar mass of Fe2O3 = (56×2) + (16×3)

= 112 + 48

= 160 g/mol

Mole of Fe2O3 =?

Mole = mass /Molar mass

Mole of Fe2O3 = 23 / 160

Mole of Fe2O3 = 0.144 mole

Next, we shall write the balanced equation for the reaction. This is given below:

2Al + Fe2O3 —> Al2O3 + 2Fe

From the balanced equation above,

1 mole of Fe2O3 reacted to produce 2 moles of Fe.

Finally, we shall determine the number of mole of Fe produced by the reaction of 23 g (i.e 0.144 mole) of Fe2O3. This can be obtained as illustrated below:

From the balanced equation above,

1 mole of Fe2O3 reacted to produce 2 moles of Fe.

Therefore, 0.144 mole of Fe2O3 will react to produce = 0.144 × 2 = 0.288 mole of Fe.

Thus, 0.288 mole of Fe is obtained from the reaction.

7 0
2 years ago
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