(a) The car is undergoing an acceleration of
so that in 9.02 s, it will have covered a distance of
The car has tires with diameter <em>d</em> = 58.5 cm = 0.585 m, and hence circumference <em>π d</em> ≈ 1.84 m. Divide the distance traveled by the tire circumference to determine how many revolutions it makes:
(b) The wheels have average angular velocity
where is the average angular velocity, and are the initial and final angular velocities (rev/s), and are the initial and final angular displacements (rev), respectively, and is the duration of the time between initial and final measurements. The second equality holds because acceleration is constant.
The wheels start at rest, so
The first one is Water
The second one is Juice
The third one Vinegar
The fourth one is Milk
The last one may be Shampoo
Besides the Sun, planets and their moons, there are still other celestial bodies in the universe. Actually, there is more than what we know of. The universe is endless and timeless. It also contains stars, comets, asteroids, meteorites and the galaxies.
Answer:
7500 m/s
Explanation:
Centripetal acceleration = gravity
v² / r = GM / r²
v = √(GM / r)
Given:
G = 6.67×10⁻¹¹ m³/kg/s²
M = 5.98×10²⁴ kg
r = 6.8×10⁵ + 6.357×10⁶ = 7.037×10⁶ m
v = √(6.67×10⁻¹¹ (5.98×10²⁴) / (7.037×10⁶))
v = 7500
The orbital velocity is 7500 m/s.
Answer:
Explanation:
Resonant frequency is 240
4π² x 240² = 1 / LC
230400π² = 1 / LC
Let the required frequency = n
inductive reactance = 2 πn L
capacitative reactance = 1 / 2 π n C
inductive reactance / capacitative reactance
= 4π² x n ² x LC = 5.68
4π² x n ² = 1 / LC x 5.68
= 230400π² x 5.68
4n ²= 230400 x 5.68
n ²= 57600 x 5.68
n ² = 327168
n = 572 approx