We know, by conservation of energy :
Therefore,
Putting given values, we get :
Therefore, the spring be compressed to 6.93 cm to send the ball twice as high.
Hence, this is the required solution.
An object is thrown directly upwards from the ground at a velocity of 9ms. Recalling that the acceleration due to gravity is −gm
1 answer:
Answer:
Explanation:
Given
Object is thrown with a velocity of
Acceleration due to gravity is -g (i.e. acting downward)
Vertical distance traveled by object is given by
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
at maximum height final velocity is zero
time taken to reach maximum height
using
v=u+at
0=9-gt
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Answer:
correct option is b. 31.3 m/s
Explanation:
given data
artificial gravity a1 = 1 g
artificial gravity a2 = 2 g
diameter = 100 m
radius r= 50 m
speed v1 = 22.1 m/s
solution
As acceleration is ∝ v²
so we can say
.....................1
put here value
solve it
v2 = × 22.1
v2 = 31.25 m/s
so correct option is b. 31.3 m/s
Answer:
Explanation:
Given
radius of circle=1.4 m
Height of stone above ground=1.5 m
Horizontal distance(R)=10 m
It is given at the time of break stone flies horizontally thus stone to cover a height of 1.5 m in time t before reaching ground
t=0.55 s
Initial horizontal velocity at the time of break is given by u
u=18.07 m/s
Therefore magnitude of centripetal acceleration is given by