Assuming the earth and the sun to be perfect spheres,
Volume of the sphere = 4/3 * pi * (r**3)
Volume of the earth = 4/3 * pi * ((4000*1.609 km)**3) = 1.116 E 12 km3
Volume of the Sun= 4/3 * pi * ((7 E 5 km)**3) = 1.436 E 18 km3
Density = mass /volume
Density of earth = 6 E 24 kg / 1.116 E 12 km3 = 5.376 E 12 [kg/km3]
Density of Sun= 2 E 30 kg / 1.436 E 18 km3 = 1.392 E 12 [kg/km3]
Density of earth / Density of Sun =
5.376 E 12 [kg/km3] / 1.392 E 12 [kg/km3] = 3.86
The correct answer is “B", second option.
Answer: a) V = 9.81 m/a
b) S = 3.905m
c) V2 = 8.29m/s
d) Yes. The speed reduces.
Explanation:
Please find the attached files for the solution
Displacement = (final position) - (initial position) = change in position.
HOPE IT HELPS YOU
Given:
1 mi = 1609 m.
Also,
1 hour = 3600 s
Therefore

Answer: 767.4 mph (nearest tenth)