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Juli2301 [7.4K]
3 years ago
14

The ionization constant (Ka) of HF is 6.7 X 10 ^-4. Which of the following is true in a 0.1 M solution of this acid?

Chemistry
2 answers:
spin [16.1K]3 years ago
8 0
The ionization equation is:

HF ⇄ H(+) + F(-)

The ionization constant is Ka = [H(+)] * [H(-)] / [HF]

=> [H(+)] * [F(-)] = Ka * [HF]

Given that Ka < 1

[H(+)] * [F(-)] < [HF]

Which is [HF] >  [H(+)] * [F(-)] the option a. fo the list of choices.
n200080 [17]3 years ago
6 0

The correct answer is [HF] is less than [H+][F-]

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Lpg contains ? (<br> a. methane (<br> b. butane (<br> c. eyhane (<br> d. none of them
disa [49]
Lpg contains ethane,propane,and butane..hope it helps
4 0
3 years ago
Calcium nitrate tetrahydrate dissolves in cold water to the extent of 266 g per 100 cm3. What is the concentration of nitrate io
Soloha48 [4]

Answer : The correct option is, (b) 22.5 M

Explanation : Given,

Mass of calcium nitrate tetrahydrate = 266 g

Molar mass of calcium nitrate tetrahydrate  = 236.15 g/mole

Volume of solution = 100cm^3=100mL

Molarity : It is defined as the moles of solute present in one liter of solution.

Formula used :

Molarity=\frac{\text{Mass of calcium nitrate tetrahydrate }\times 1000}{\text{Molar mass of calcium nitrate tetrahydrate }\times \text{volume of solution in ml}}

Now put all the given values in this formula, we get:

Molarity=\frac{266g\times 1000}{236.15g/mole\times 100ml}=11.26mole/L=11.26M

As calcium nitrate tetrahydrate dissociate to give 1 mole of calcium ion, 2 moles of nitrate ion and 4 moles of water.

The concentration of nitrate ion = 2\times 11.26M=22.5M

Thus, the concentration of nitrate ion is, 22.5 M

4 0
3 years ago
Write the Lewis structure for the following<br> H20<br> So2
Tasya [4]

See the sketch attached.

<h3>Explanation</h3>

The Lewis structure of a molecule describes

  • the number of bonds it has,
  • the source of electrons in each bond, and
  • the position of any lone pairs of electrons.

Atoms are most stable when they have eight or no electrons in their valence shell (or two, in case of hydrogen.)

  • Each oxygen atom contains six valence electrons. It demands <em>two</em> extra electrons to be chemically stable.
  • Each sulfur atom contains six valence electrons. It demands <em>two </em> extra electrons to be chemically stable.
  • Each hydrogen atom demands <em>one</em> extra electron to be stable.

H₂O contains two hydrogen atoms and one oxygen atom. It would take an extra 2 + 2  × 1 = 4 electrons for all its three atoms are stable. Atoms in an H₂O would achieve that need by sharing electrons. It would form a total of 4 / 2 = 2 O-H bonds.

Each O-H bond contains one electron from oxygen and one from hydrogen. Hydrogen has no electron left. Oxygen has six electrons. Two of them have went to the two O-H bonds. The remaining four become 4 / 2 = 2 lone pairs. The lone pairs repel the O-H bonds. By convention, they are placed on top of the two H atoms.

Similarly, atoms in a SO₂ molecule demands an extra 2 × 2 + 2 = 6 electrons for its three atoms to become chemically stable. It would form 6 / 2 = 3 chemical bonds. Loops are unlikely in molecules without carbon. As a result, one of the two O atoms would form two bonds with the S atom while the other form only one.

Atoms are unstable with an odd number of valence electrons. The S atom in SO₂ would have become unstable if it contribute one electron to each of the three bond. It would end up with 3 × 2 + 3 = 9 valence electrons. One possible solution is that it contributes two electrons in one particular bond. One of the three bonds would be a coordinate covalent bond, with both electrons in that bond from the S atom. In some textbooks this type of bonds are also known as dative bonds.

Dots and crosses denotes the origin of electrons in a bond. Use the same symbol for electrons from the same atom. Electrons from the oxygen atoms O are shown in blue in the sketch. They don't have to be colored.

7 0
3 years ago
Im hvaing a hard time getting the right answer
Tanya [424]

Answer:

V=23.9mL

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

n=2.49g*\frac{1mol}{125.55 g}=0.0198mol

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

M=\frac{n}{V}\\\\V=\frac{n}{M}

By plugging in the moles and molarity, we obtain:

V=\frac{0.0198mol}{0.830mol/L}=0.0239L

Which in mL is:

V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL

Best regards!

6 0
3 years ago
Your boss tells you that water at 68 F is flowing in a cooling tower loop at a rate of 600 gpm, in an 8-inch inside diameter pip
avanturin [10]

Explanation:

The volumetric flow rate of water will be as follows.

       q = 600 gpm \times \frac{0.000063 m^{3} s^{-1}}{1 gpm}

         = 0.0378 m^{3}/s&#10;

    Diameter = 8 in \times \frac{0.0254 m}{1 in}

                   = 0.2032 m

Relation between area and diameter is as follows.

           A = \frac{\pi}{4} \times D^{2}

               = \frac{3.14}{4} \times (0.2032 m)^{2}

               = 0.785 x 0.2032 x 0.2032

               = 0.0324 m^{2}

Also,     q = A × V

or,         V = \frac{q}{A}

                = \frac{0.0378 m^{3}/s}{0.0324 m^{2}}

                = 1.166 m/s

As, viscosity of water = 1 cP = 10^{-3} Pa-s

Density of water = 1000 kg/m^{3}

Therefore, we will calculate Reynolds number as follows.

 Reynolds number = \frac{D \times V \times density}{viscosity}

                                 = \frac{0.2032 m \times 1.166 m/s  \times 1000}{10^{-3}}  

                                = 236931.2

Hence, the flow will be turbulent in nature.

Thus, we can conclude that the Reynolds number is 236931.2 and flow is turbulent.

8 0
3 years ago
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