The ionization constant (Ka) of HF is 6.7 X 10 ^-4. Which of the following is true in a 0.1 M solution of this acid?

2 answers:

8 0

The ionization equation is:

HF ⇄ H(+) + F(-)

The ionization constant is Ka = [H(+)] * [H(-)] / [HF]

=> [H(+)] * [F(-)] = Ka * [HF]

Given that Ka < 1

[H(+)] * [F(-)] < [HF]

Which is [HF] > [H(+)] * [F(-)] the option a. fo the list of choices.

n200080 [17]3 years ago

6 0

The correct answer is [HF] is less than [H+][F-]

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Hello there!

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